Suppose you are an elementary school teacher. You want to order a rectangular bulletin board to mount on a classroom wall that has an area of 90 square feet. Suppose fire code requirements allow for no more than 30% of a classroom wall to be covered by a bulletin board. If the length of the board is three times as long as the width, what are the dimensions of the largest bulletin board that meets fire code?

Answers

Answer 1
Answer:

Answer:

3 feet wide and 9 feet long.

Step-by-step explanation:

The classroom wall has an area of 90ft^2.

The fire code requirements allow a bulletin board with an area of at most 30% of 90ft^2. This means that the maximum area of the bulletin board is 27ft^2

Let L and W be the length and wide of the bulletin board.  

If the length of the board is three times as long as the width, then L=3W, and the area of the board is LW=3WW=3W^2

For the largest board we have, 3W^2=27 \Rightarrow W^2=(27)/(3)=9 \Rightarrow W=√(9)=3ft

So, the largest bulletin board that meets the fire code is 3 ft. wide and 9 ft. long.


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Thirty 7th graders were surveyed and asked their favorite sport. The results showed that 15 liked football, 7 liked baseball, 5 like basketball, and 3 like soccer. What generalization can not be made?Soccer is the least favorite sport. Half of the students like football. The students would prefer to play sports over going to school.None of the students like tennis.
Which number is closest to the square root of 84 ?
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You have been saving dimes for long time and take all of them to the bank to exchange for dollar bills. the teller weighs the dimes and records a total mass of 3358 g. of a dime has an average mass of 2:30g. how much money are you owed? chemistry

Answers

Since 2:30 gm so 1 dime is 15 grams . So if we divide the total mass/ individual mass = 3358/15 =223.866 approx 224 dimes.

How are 0.5 and 0.05 and 0.0005 related

Answers

\bf \cfrac{5}{10}\cdot \cfrac{1}{10}\implies \cfrac{5}{100}~\hspace{10em}\cfrac{5}{100}\cdot \cfrac{1}{10}\implies \cfrac{5}{1000}\n\n\n\textit{we can say one is \boxed{\textit{one tenth of the other}}}\n\n[-0.35em]~\dotfill\n\n\cfrac{5}{100}\cdot 10\implies \cfrac{5}{10}~\hspace{10em}\cfrac{5}{1000}\cdot 10\implies \cfrac{5}{100}\n\n\n\textit{or we can say, one is \boxed{\textit{ten times the other}}}

On a test, Avery lost 5points for each of the 6
questions she got wrong
but earned 10 points for
answering the bonus
question correctly. What
integer represents her
score in relation to a
perfect score of 100?

Answers

Answer:

bruhhhhhhhhhhhhhhhhhhhhhhhhhh

If an artist has 14 pounds of clay and she uses 5 1/4 pounds. How many pounds of clay will she have left?

Answers

Answer: She will have 1.75 pounds of clay left

Step-by-step explanation: you need to divide 51/4 and it is 12.75 and then you subtract 14-12.75 and get = 1.25

Answer:

She will have 8 and 3/4 | 8.75

Step-by-step explanation:

First you subtract the whole numbers,

14 - 5 = 9

Then because you have no fraction you take a whole number and split it into 4/4 or = 1 whole

4/4 - 1/4 = 3/4

She will have 8 and 3/4 or 8.75

5Type the correct answer in each box.
50°
60°
709
Х
50°
The value of xis
o, and the value of yis

Answers

Answer:

x = 60°

y = 50°

Step-by-step explanation:

✅x = 180° - (50° + 70°) (sum of interior angles of a triangle theorem)

x = 180° - 120°

x = 60°

✅Based on the exterior angle theorem, the sum of the opposite interior angles of a triangle = the exterior angle.

Therefore,

50° + 60° = x + y

Plug in the value of x

50° + 60° = 60° + y

110° = 60° + y

y = 110° - 60°

y = 50°

The weights, in pounds, of the cats in an animal adoption center are normally distributed. If a random sample of cats is taken and the confidence interval is (7.9,12.7), what is the margin of error

Answers

Answer: 2.4

Step-by-step explanation:

Given : The weights, in pounds, of the cats in an animal adoption center are normally distributed.

The confidence interval is (7.9,12.7)           (1)

Let \overline{x} be the sample mean of the weights, in pounds, of the cats in an animal adoption center.

We know that the confidence interval for population mean is given by :-

(\overline{x}-E,\overline{x}+E)      (2)

From (1) and (2)

\overline{x}-E=7.9-------(3)\n\n\overline{x}+E=12.7--------------(4)

Subtracting (3) from (4), we get

2E=4.8\n\n\Rightarrow\ E=2.4

Hence, the margin of error is E = 2.4