Answer:
C. The students would prefer to play sports over going to school
Step-by-step explanation:
Hope this helps :)
can u brainlist
Answer:
p = 0.48
Step-by-step explanation:
A binomial experiment is and experiment with n trials, every trial is identical and independent and every trial has the same probability p of success and 1-p of fail.
Then, we have a binomial experiment of 16 trials. it means that every trial has the same conditions. So, if the probability of success on trial 9 is 0.48, the probability of success on trial 13 is also 0.48.
question is below
The missing justification is for the statement that three angles add to a particular angle. The appropriate choice is ...
... c. Angle Addition Postulate
Answer:
Check pdf
Step-by-step explanation:
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▹ Answer
18x⁴ + 36x³ - 9x²
▹ Step-by-Step Explanation
9x²(4x + 2x² - 1)
36x³ + 18x⁴ - 9x²
18x⁴ + 36x³ - 9x²
Hope this helps!
CloutAnswers ❁
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Answer:
a) The probability of getting a seven is 4/52
b) At least one of the cards is a seven=0.2813
c) The probability that none of them are seven= 0.7187
d) The probability that two out the four cards is a seven= 0.043
Step-by-step explanation:
A deck contains 52 cards containing 4 sets of 13 cards . Each set has a seven card in it. Thus there are 4 seven cards in a deck of 52 cards.
a) The probability of getting a seven is 4/52=0.0769
b) At least one of the cards is a seven=
1- P(no seven)
= 1- 4C0 * 48C4/ 52C4= 1- 0.7187= 0.2813
c) The probability that none of them are seven=4C0 * 48C4/ 52C4= 0.7187
d) The probability that two out the four cards is a seven= First card is seven * second Card is seven * two cards are not seven
= 4/52* 3/51*48/50= 0.0769*0.0588*0.96= 0.043
The probability of drawing four sevens, at least one seven, no sevens, and exactly two sevens from a shuffled deck of cards is explained step-by-step.
(a) The deck contains 52 cards, out of which there are 4 sevens. So, the probability of drawing a seven on the first card is 4/52. After drawing the first seven, there are 51 cards left in the deck, including 3 sevens. So, the probability of drawing a seven on the second card is 3/51. Continuing this process, the probability of getting four sevens in a row is (4/52) * (3/51) * (2/50) * (1/49).
(b) The probability of at least one seven can be calculated by finding the probability of the complement event (no seven). The probability of no seven on the first card is 48/52. After drawing the first card, there are 51 cards left, so the probability of no seven on the second card is 47/51. Continuing this process, the probability of no seven in four cards is (48/52) * (47/51) * (46/50) * (45/49). Subtracting this probability from 1 gives us the probability of at least one seven.
(c) The probability of none of the four cards being a seven can be calculated similarly to part (b). The probability of no seven on the first card is 48/52. After drawing the first card, there are 51 cards left, so the probability of no seven on the second card is 47/51. Continuing this process, the probability of no seven in four cards is (48/52) * (47/51) * (46/50) * (45/49).
(d) To find the probability that exactly two of the four cards are sevens, we need to consider two cases: (1) the first two cards are sevens and the last two are not, and (2) the first two cards are not sevens and the last two are. The probability of the first case is (4/52) * (3/51) * (48/50) * (47/49), and the probability of the second case is (48/52) * (47/51) * (4/50) * (3/49). Adding these probabilities gives the total probability.
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