Question 1Two packs of toilet rolls are available in the
supermarket 9 toilet rolls for £3.15 4 toilet rolls for £1.36
Work out which pack offers the best value for money.

Answers

Answer 1
Answer:

Answer:

for the nine toilet pack, a toilet roll is 3.15/9 which is£0.35 while for the 4 toilet roll pack, a toilet roll is 1.36/4 which is £0.34 so the nine toilet pack gives the best value for money because a toilet roll sells for £0.35 which is £ 0.01 more than the four toilet pack


Related Questions

A committee at the College Board has been asked to study the SAT math scores for students in Pennsylvania and Ohio. A sample of 45 students from Pennsylvania had an average score of 580, whereas a sample of 38 students had an average score of 530. The sample standard deviations for Pennsylvania and Ohio are 105 and 114 respectively. Does the study suggest that the SAT math score for students in Pennsylvania and Ohio differ
What percent of 68 is 34
Whats the equavalent to log8 64+log8 8
Is a tree decaying 10% each six weeks a quadratic function?
What can be the last digit of the fourth power of a natural number?

Find the answer for 10 + 10

Answers

Answer:20

Step-by-step explanation:

Find the value of x.



x=

Answers

Answer:

my guess is 135 because there both the same corners

Step-by-step explanation:

Answer:

110

Step-by-step explanation:

900-(105+150+140+135+125+135)= 110

The Ericsson method is one of several methods claimed to increase the likelihood of a baby girl. In a clinical​ trial, results could be analyzed with a formal hypothesis test with the alternative hypothesis of pgreater than​0.5,which corresponds to the claim that the method increases the likelihood of having a​ girl, so that the proportion of girls is greater than 0.5. If you have an interest in establishing the success of the​ method, which of the following​ P-values would you​ prefer: 0.999,​ 0.5, 0.95,​ 0.05, 0.01,​ 0.001? Why?

Answers

Answer:

0.001

Step-by-step explanation:

Here, the aim is to support the null hypothesis, Ha. Where Ha: p > 0.5. Which means we are to reject null hypothesis H0. Where H0: p = 0.5.

The higher the pvalue, the higher the evidence of success. We know If the pvalue is less than level of significance, the null hypothesis H0 is rejected.

Hence the smallest possible value 0.001 is preferred as the pvalue because it corresponds to the sample evidence that most strongly supports the alternative hypothesis that the method is effective

Graph the line with slope 1/2 passing through the poin

Answers

Answer:

See explanation below.

Step-by-step explanation:

To make use of the tools they give you, start at the point (-5, -2) which you know is a point the line goes through, then draw a line that goes towards the right following the rule given by the slope "1/2" (rise/run) which means that every 2 units to the right, you go one unit up. so from the point -5 in x, you go to the point -3 in x, and from -2 in y you move up one unit to -1

Therefore the line joins (-5, -2) to the point (-3, -1)

Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this lesson to solve the following exercise. Find the following sums without using a calculator or a formula. Hint: Apply the procedure used by Gauss. (See the Math Matters on page 31.) (a) 1 + 2 + 3 + 4 + . . . + 397 + 398 + 399 + 400 (b) 1 + 2 + 3 + 4 + . . . + 542 + 543 + 544 + 545 (c) 2 + 4 + 6 + 8 + . . . + 72 + 74 + 76 + 78

Answers

these question give me headache

Final answer:

This answer uses Gauss's method to effectively find the sum of arithmetic series without a calculator or formula. By pairing numbers at the start and end of the series, a constant sum is found which can be easily multiplied by the number of pairs, providing the total sum of series. The sums are 80200, 149238, and 1560 respectively for the given scenarios.

Explanation:

To solve a series of summations without the use of a calculator or formula, we can apply a method used by Gauss. This problem relates to the concept of arithmetic series in mathematics.

  1. Step 1: Understand the problem. We're asked to find the sum of certain series. This involves adding all the numbers in the series together.
  2. Step 2: Devise a plan. The strategy that Gauss used was to pair numbers at the start and end of an arithmetic series. This way, each pair totals the same sum, making it easier to solve.
  3. Step 3: Carry out the plan.
    1. (a) Sum of 1 to 400: Pair numbers (1+400, 2+399, 3+398, etc.), every pair equals 401. There're 200 pairs, so 401*200 = 80200.
    2. (b) Sum of 1 to 545: Same strategy. Each pair (1 + 545, 2 + 544, 3 + 543, etc.) equals 546. There're 273 pairs, so the sum is 546*273 = 149238.
    3. (c) Sum of even numbers from 2 to 78: Notice it is an arithmetic series (2, 4, ...78). The first term a = 2 and last term l = 78. There're 39 terms. By using formula for arithmetic series (n/2)*(a + l), we have (39/2) * (2 + 78) = 1560.
  4. Step 4: Look back. Confirm the plan was executed correctly by reviewing the steps taken.

Learn more about Sum of Series here:

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Suppose you're given the formula q = 2o + 6p. If you know that p = o – 7, how could you rewrite the formula?

Answers

Answer:

q = 8o - 42

Step-by-step explanation:

Given:  The given formula is q = 2o + 6p.

p = o – 7

Now we have to plug in p = o - 7 in the given formula, we get

q = 2o + 6(o - 7)

Now we use the distributive property a(b-c) =ab - ac and expand.

q = 2o + 6o -6(7)

q = 2o +6o - 42

Here 2o and 6o are the like terms, we can add them

q = 8o - 42

q = 2o + 6p

p = o – 7

⇒ q = 2o + 6(o - 7) = 2o + 6o - 6 × 7 = 8o - 42

⇒ q = 8o - 42