You suspect that a power supply is faulty, but you use a power supply tester to measure its voltage output and find it to be acceptable. Why is it still possible that the power supply may be faulty?

Answers

Answer 1

Answer:

While a power supply tester can be a useful tool for quickly checking voltage output, it might not reveal all the potential issues a faulty power supply can cause.

Even if a power supply tester shows that the voltage output of a power supply is within acceptable limits, it's still possible that the power supply may be faulty. Here's why:

1. Voltage Under Load: A power supply tester might only measure the voltage output under no load or very light load conditions.

A faulty power supply might provide the correct voltage at low loads but fail to deliver stable voltage under high loads, which could lead to system instability or crashes.

2. Voltage Ripple and Noise: Power supplies are expected to provide a stable and clean output voltage.

3. Short Circuits or Overloads: A power supply tester typically doesn't simulate the behavior of a real system.

4. Intermittent Issues: Faulty power supplies can exhibit intermittent issues. The power supply might work fine during the testing but fail when subjected to extended periods of operation or specific conditions.

5. Quality of Components: A power supply tester might not assess the quality of individual components within the power supply.

6. Compatibility Issues: Some power supplies might not be fully compatible with certain computer hardware. Even if the voltage seems fine, compatibility issues can still cause problems.

Learn more about Short Circuit here:

brainly.com/question/30778363

#SPJ12

Related Questions

The index of refraction for red light in water is 1.331, and that for blue light is 1.340. If a ray of white light enters the water at an angle of incidence of 83.00o , what are the underwater angles of refraction for the blue and red components of the light
Select all the statements regarding electric field line drawings that are correct. Group of answer choices: 1. Electric field lines are the same thing as electric field vectors. 2. Electric field line drawings allow you to determine the approximate direction of the electric field at a point in space. 3. The number of electric field lines that start or end at a charged particle is proportional to the amount of charge on the particle. 4. The electric field is strongest where the electric field lines are close together.
g During a collision with a wall, the velocity of a 0.4 KgKg ball changes from 25 m/sm/s towards the vall to 12 m/sm/s away from the wall. If the time the ball was in contact with the call was 0.5 secsec , what was the magnitude of the avarage force applied to the ball
What is the meaning of relative as a noun?
You're driving along at 25 m/s with your aunt's valuable antiques in the back of your pickup truck when suddenly you see a giant hole in the road 55 m ahead of you. Fortunately, your foot is right beside the brake and your reaction time is zero! Can you stop without the antiques sliding and being damaged? Their coefficients of friction are μs=0.6 and μk=0.3. Hint: You're not trying to stop in the shortest possible distance. What's your best strategy for avoiding damage to the antiques?

Q18: A cube of aluminum has an edge length of 20 cm. Aluminum has adensity of 2.7 g/cm and a specific heat of 0.217 cal/ g.°С. When
the internal energy of the cube increases by 47000 cal its temperature
increases by:
A
B
C
D
E
5 °C
10 °C
20 °C
100 °C
200 °C

Answers

The change in temperature of this cube of aluminum is equal to: B. 10°C

Given the following data:

Edge length, L = 20 cm.

Density of Aluminum = 2.7 g/cm

Specific heat capacity (C) of aluminum = 0.217 Cal/g°С

Internal energy = 47000 calories.

To find the change in temperature of this cube of aluminum:

First of all, we would determine the volume of this cube of aluminum.

$Volume \;of \;a \;cube = L^3\n\nVolume \;of \;a \;cube = 20^3\n\nVolume \;of \;a \;cube = 8000\; cm^3$

Next, we calculate the mass of this cube of aluminum:

$Mass = Density * Volume\n\nMass = 2.7 * 8000$

Mass = 21,600 grams.

Now, we can find the change in temperature of this cube of aluminum:

Mathematically, the quantity of heat energy is given by the formula;

$Q = mc\theta$

Where:

Q represents the quantity of heat energy.

m represents the mass of an object.

c is the specific heat capacity.

∅ is the change in temperature.

Substituting the parameters into the formula, we have;

$47000 = 21600 * 0.217 * \theta\n\n47000 = 4687.2 \theta\n\n \theta =(47000)/(4687.2) \n\n \theta = 10.03$

Change in temperature = 10°C

Answer:

10 °C

Explanation:

From the question given above, the following data were obtained:

Egde length (L) of aluminum = 20 cm

Density of Aluminum = 2.7 g/cm³

Specific heat capacity (C) of aluminum = 0.217 cal/ g°С

Heat (Q) energy = 47000 cal

Change in Temperature (ΔT) =?

Next, we shall determine the volume of the aluminum. This can be obtained as follow:

Egde length (L) of aluminum = 20 cm

Volume (V) of aluminum =?

V = L³

V = 20³

V = 8000 cm³

Thus, the volume of the aluminum is 8000 cm³

Next, we shall determine the mass of the aluminum. This can be obtained as follow:

Density of Aluminum = 2.7 g/cm³

Volume of Aluminum = 8000 cm³

Mass of aluminum =.?

Density = mass/volume

2.7 = mass /8000

Cross multiply

Mass of aluminum = 2.7 × 8000

Mass of Aluminum = 21600 g

Finally, we shall determine the change in temperature of the aluminum as follow:

Specific heat capacity (C) of aluminum = 0.217 Cal/g°С

Heat (Q) energy = 47000 Cal

Mass (M) of Aluminum = 21600 g

Change in Temperature (ΔT) =?

Q = MCΔT

47000 = 21600 × 0.217 × ΔT

47000 = 4687.2 × ΔT

Divide both side by 4687.2

ΔT = 47000 / 4687.2

ΔT = 10 °C

Therefore, the increase in the temperature of the aluminum is 10 °C.

What is an atomic nucleus

Answers

Answer:

The atomic nucleus is the small, dense region consisting of protons and neutrons at the center of an atom, discovered in 1911 by Ernest Rutherford based on the 1909 Geiger–Marsden gold foil experiment.

Explanation:

A sphere has a charge of −84.0 nC and a radius of 5.00 cm. What is the magnitude of its electric field 3.90 cm from its surface?

Answers

Answer:

$E = -9.5* 10^4~N/C$

Explanation:

Gauss' Law should be applied to find the E-field 3.9 cm from the surface of the sphere.

In order to apply Gauss' Law, an imaginary spherical shell (Gaussian surface) should be placed around the original sphere. The exact position of the shell must be 3.9 cm from the surface of the original sphere.

Gauss' Law states that

$\int {\vec{E}d\vec{a}} = (Q_(enc))/(\epsilon_0)$

Here, the integral in the left-hand side is equal to the area of the imaginary surface. After all, the reason behind choosing the imaginary surface a spherical shell is to avoid this integral. The enclosed charge in the right-hand side is equal to the charge of the sphere, -84.0 nC. The radius of the imaginary surface must be 5 + 3.9 = 8.9 cm.

So,

$E4\pi r^2 = (-84* 10^(-9))/(8.8* 10^(-12))\nE4\pi (8.9 * 10^(-2))^2 = (-84* 10^(-9))/(8.8* 10^(-12))\n\nE = -9.5* 10^4~N/C$

PLEASE HELP!!! Sophia says that if we add two electrons to oxygen in order to fill its valence shell, it’s expected charge would be +2. Is she correct? If not, explain the error in her thinking.

Answers

The error in her thinking is that oxygen has has six electrons and a negative charge is acquired by nitrogen when it gains two electrons.

Oxygen is a member of group 16. The elements in group 16 has six valence electrons. This means that they need an extra two electrons to complete their octet.

If an atom gains two electrons, it will have a charge of -2 and not +2, a positive charge means that the atom lost electrons. Nonmetals like oxygen do not loose electrons rather they gain electrons.

Learn more: brainly.com/question/14156701

During a storm, a tree limb breaks off and comes to rest across a barbed wire fence at a point that is not in the middle between two fence posts. The limb exerts a downward force of 176 N on the wire. The left section of the wire makes an angle of 12.5° relative to the horizontal and sustains a tension of 413 N. Find the (a) magnitude and (b) direction (as an angle relative to horizontal) of the tension that the right section of the wire sustains.

Answers

Answer:

a. 12.12°

b. 412.04 N

Explanation:

Along vertical axis, the equation can be written as

T_1 sin14 + T_2sinA = mg

T_2sinA = mg - T_1sin12.5 ....................... (a)

Along horizontal axis, the equation can be written as

T_2×cosA = T_1×cos12.5 ......................... (b)

(a)/(b) given us

Tan A = (mg - T_1sin12.5) / T_1 cos12.5

= (176 - 413sin12.5) / 413×cos12.5

A = 12.12 °

(b) T2 cosA = T1 cos12.5

T2 = 413cos12.5/cos12.12

= 412.04 N

Answer:

Magnitude - 11.83 Degree

Direction - 422.42 N

Explanation:

Given data:

Downward force on wire 176 N

Angle made by left section of wire 12.5 degree with horizontal

Tension force = 413 N

From figure

Applying quilibrium principle at point A

The vertical and horizontal force is 0

then we have

$Tcos\theta = 413 N$ ........1

$176 = 413 sin 12.5 + Tsin\theta$ .......2

$Tsin\theta = 176 - 89.39 = 86.6$ .......3

divide equation 3 by 1

we get

$\theta = tan^(-1) (0.2096)$

$theta = 11.83^o$ ...........4

from equation 3 and 4

$T = (86.6)/(sin 11.83)$

T = 422.42 N

A long wire carries a current toward the south in a magnetic field that is directed vertically upward. What is the direction of the magnetic force on the wire?

Answers

Answer:

the answer is it is going north

Explanation:

because its the opposite

Final answer:

The magnetic force on a wire carrying current towards the south under a magnetic field directed vertically upwards will point towards the East. In order to determine this, use the right-hand rule.

Explanation:

The direction of the magnetic force on a current-carrying wire under a magnetic field can be deduced using the right-hand rule. In this case, with the current flowing towards the south and the magnetic field directed vertically upward, you would point your right thumb in the direction of the current (southwards) and curl your fingers in the direction of the magnetic field (upwards). The palm of your hand will then face toward the direction of the force. In this case, the force would be pointing toward the East.

The right-hand rule is a vital principle in the study of electromagnetism as it aids in identifying the direction of various quantities in magnetic fields. The magnetic force on a current-carrying wire represents the phenomenon underlying the working of many electric motors.

Learn more about Magnetic Force here:

brainly.com/question/10353944

#SPJ5

Other Questions

The acceleration due to gravity on Earth is 9.80 m/s2. If the mass of a honeybee is 0.000100 kilograms, what is the weight of this insect?

While the block hovers in place, is the density of the block (top left) or the density of the liquid (bottom center) greater?

Which of the following types of waves is not part of the electromagnetic spectrum? A) microwaves B) gamma rays C) ultraviolet radiation D) radio waves E) sound waves

A foot is 12 inches and a mile is 5280I ft exactly. A centimeter is exactly 0.01m or mm. Sammy is 5 feet and 5.3tall. what is Sammy's height in inches?