Answer:
In parallel combination, the capacity of each capacitor is 11 F.
In series combination, the capacity of each capacitor is 44 F.
Explanation:
Let there are two capacitors each of capacitance C.
When they are connected in parallel:
In parallel combination, the effective capacitance is Cp.
Cp = C1 + C2 = C + C
22 = 2 C
C = 11 F
When they are connected in series:
In parallel combination, the effective capacitance is Cs.
1 / Cs = 1 / C1 + 1 / C2 = 1 / C + 1 / C = 2 / C
1 / 22 = 2 / C
C = 44 F
Answer:
Time = 1.61 seconds
Explanation:
Using the equation displacement of a trajectory motion in the y plane
Y = u t sin ů - ½gt²....equation 1 where
Y= vertical displacement =4.1
U = initial velocity = 15m/s
g = acc. Due to gravity = 10m/s
Ů = angle of trajectory = 45
t = time to reach fan on its way down
Sub into equ 1
4.1 = 15t sinů - ½ * 10t²
4.1 = 10.61t - 5t²
Solve using quadratic formula
t =[-B±( -B² -4AC)^½]/2A....equation 2
Where A = 5, B=10.61, C =4.1
Substitute A,B,C into equ2
t = (10.61±5.53)/10
t = 0.508seconds or 1.61seconds
Since it is on its way down t= 1.61 seconds
Answer:
(c) 3P/5
Explanation:
The formula to calculate the power is:
where
W is the work done
T is the time required for the work to be done
In the second part of the problem, we have
Work done: 3W
Time interval: 5T
So the power required is
Answer:
The correct answer is d. tension pneumothorax.
Explanation:
The increasing build-up of air that is in the pleural space is what we call the tension pneumothorax and this happens due to the lung laceration that lets the air to flee inside the pleural space but it does not return.
Answer:
c
Explanation:
1.8 x 10⁻⁵J
The energy (E) stored in a capacitor of capacitance, C, when a voltage, V, is supplied is given by;
E = x C x V² -------------------(i)
Now, from the question;
C = 2.00μF = 2.00 x 10⁻⁶F
V = 18.0V
Substitute these values into equation (i) as follows;
E = x 2.00 x 10⁻⁶ x 18.0
E = 1.8 x 10⁻⁵J
Therefore, the quantity of energy stored in the capacitor is 1.8 x 10⁻⁵J
Answer:
1.8 x 10⁻⁵J.
Explanation:
E = 1/2 x C x V²
Where,
E = energy stored in a capacitor
C = capaciitance
V = Voltage
From the question, given:
C = 2.00μF
= 2.00 x 10⁻⁶F
V = 18.0V
E = 1/2 x 2.00 x 10⁻⁶ x 18.0
= 1.8 x 10⁻⁵J.
car can accelerate at -3.5 m/p/s, how far would it take her to stop?
Answer:
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Explanation: