Answer:
a. 12.12°
b. 412.04 N
Explanation:
Along vertical axis, the equation can be written as
T_1 sin14 + T_2sinA = mg
T_2sinA = mg - T_1sin12.5 ....................... (a)
Along horizontal axis, the equation can be written as
T_2×cosA = T_1×cos12.5 ......................... (b)
(a)/(b) given us
Tan A = (mg - T_1sin12.5) / T_1 cos12.5
= (176 - 413sin12.5) / 413×cos12.5
A = 12.12 °
(b) T2 cosA = T1 cos12.5
T2 = 413cos12.5/cos12.12
= 412.04 N
Answer:
Magnitude - 11.83 Degree
Direction - 422.42 N
Explanation:
Given data:
Downward force on wire 176 N
Angle made by left section of wire 12.5 degree with horizontal
Tension force = 413 N
From figure
Applying quilibrium principle at point A
The vertical and horizontal force is 0
then we have
........1
.......2
.......3
divide equation 3 by 1
we get
...........4
from equation 3 and 4
T = 422.42 N
Answer:
Acceleration = 8.27 cm/s²
Explanation:
We are given;
initial velocity; v_i = 10.5 cm/s
Initial position; x_i = 2.72 cm
Time; t = 2.30 s
final position; x_f = 5.00 cm
To find the acceleration, we will make use of the formula;
x_f - x_i = (v_i * t) - (½at²)
Plugging in the relevant values, we have;
5 - 2.72 = (10.5 × 2.3) - (½ × a × 2.3²)
2.28 = 24.15 - 2.645a
24.15 - 2.28 = 2.645a
2.645a = 21.87
a = 21.87/2.645
a = 8.27 cm/s²
Using the kinematic equation, the acceleration of the object was calculated to be approximately8.27 cm/s² given its initial velocity, position, time, and final position.
We are given:
Initial velocity (vᵢ) = 10.5 cm/s
Initial position (xᵢ) = 2.72 cm
Time (t) = 2.30 seconds
Final position () = 5.00 cm
We want to find the acceleration (a) of the object using the kinematic equation:
x₋ᵢ - xᵢ = (vᵢ * t) - (1/2) * a * t²
Now, let's substitute the given values:
5.00 cm - 2.72 cm = (10.5 cm/s * 2.30 s) - (1/2) * a * (2.30 s)²
Simplify the equation:
2.28 cm = 24.15 cm - (1/2) * a * 5.29 s²
Now, isolate 'a' by rearranging the equation:
-1.09 cm = (-1/2) * a * 5.29 s²
To remove the negative sign, multiply both sides by -1:
1.09 cm = (1/2) * a * 5.29 s²
Next, solve for 'a' by multiplying both sides by (2 / 5.29):
a ≈ (1.09 cm) / (2 / 5.29) s²
a ≈ 8.27 cm/s²
So, the acceleration of the object is approximately 8.27 cm/s².
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In plate tectonics theory, transform boundaries occur when two plates slide past each other, divergent boundaries occur when two plates move away from each other, and convergent boundaries occur when two plates collide. A volcano is most likely to occur at a divergent boundary because the plates move away from each other, allowing magma from the mantle to reach the surface and create new crust.
In plate tectonics theory, Transform boundaries occur when two plates slide past each other horizontally, creating earthquakes. Divergent boundaries occur when two plates move away from each other, creating volcanic activity.
Convergent boundaries occur when two plates collide, and depending on the type of plates involved, can result in volcanic activity as one plate is forced beneath the other.
A volcano is most likely to occur at a divergent boundary because the plates move away from each other, allowing magma from the mantle to reach the surface and create new crust.
The Richter scale indicates the magnitude of an earthquake. The figure drawn by the needle during shaking is an outcome of earthquake's energy. This energy is what results in seismic waves travelling through various layers of earth causing shaking on the surface.
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Answer:
8m/s
Explanation:
Vavg= 16-0/2=8m/s
Answer:
a) 8.99*10³ V b) 4.5*10⁻² J c) 0 d) 0
Explanation:
a)
b)
c)
d)
Answer:
5N
Explanation:
Given parameters:
Original length = 22cm
Spring constant, K = 50N/m
New length = 32cm
Unknown
Force applied = ?
Solution:
The force applied on a spring can be derived using the expression below;
Force = KE
k is the spring constant
E is the extension
extension = new length - original length
extension = 32cm - 22cm = 10cm
convert the extension from cm to m;
100cm = 1m;
10cm will give 0.1m
So;
Force = 50N/m x 0.1m = 5N
To calculate the force used to stretch the spring, Hooke's Law is utilized, which leads to the conclusion that a force of 5 N was exerted to stretch the spring from its original length of 22 cm to a final length of 32 cm.
The force exerted by a spring is governed by Hooke's Law, which states that the force required to stretch or compress a spring by a certain distance is proportional to that distance. In this case, the spring constant, k, is given as 50 N/m and the spring is stretched from its original length of 22 cm to a final length of 32 cm. This represents a stretch, or displacement, of 10 cm (or 0.1 m when converted to the standard unit).
The force (F) can be calculated using Hooke's law: F = kx, where x is the displacement of the spring. Substituting the given values, the force amounts to F = (50 N/m) * (0.1 m) = 5 N. Therefore, the force used to stretch the spring to its final length of 32 cm is 5 N.
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(b) How far is the probe from Earth when its batteries fail, as measured by mission control?
ly
(c) How far is the probe from Earth, as measured by its built-in trip odometer; when its batteries fail?
ly
Answer:
22.26 years
, 15.585 light years , 11.13 light years
Explanation:
a)
=
= 22.26 years
b)
0.7*c*22.26 years
=15.585 light years
c)
0.7*c*15.9
=11.13 light years