PLEASE HELP ASAP!!1. what is the pOH of a solution if the pH is 2.23?

A. pOH=13
B. pOH=11.77
C. pOH=8.52
D. pOH=10.52

2. what is the pOH of a solution if the pH is 2.23

A. pOH=1
B. pOH=12
C. pOH=8
D. pOH=9

3. Given a solution of perchloric acid has a concentration of .023M, what is the pH and pOH

A. pH=2.3 and pOH=11.97
B. pH=1.64 and pOH= 12.36
C. pH=4.5 and pOH=9.95

Answers

Answer 1
Answer: 1) POH=14-2.23=11.77
2)B
3)HClO4=H+ +clo4—
C(H+)=0.023 M
pH=-log[H+]=1.63
POH=14-1.63=12.37
Answer 2
Answer:

Final answer:

The pH and pOH for a solution are related through the equation pH + pOH = 14. The pOH for solutions with a pH of 2.23 is 11.77, and in a solution of perchloric acid with a concentration of .023M, the pH is 1.64 and pOH is 12.36.

Explanation:

The concept of pOH and pH are related through the equation pH + pOH = 14 at 25 °C. If you have the value of one, you can easily find the other. For your first two questions, the pH of solution is given as 2.23. Therefore, the pOH would be 14 - 2.23 = 11.77. Your answer to both questions 1 and 2 is B. pOH=11.77.

For question 3, the perchloric acid has a concentration of .023M. To find the pH, we calculate -log[H3O+], which gives about 1.64. Therefore, the pOH would be 14 - 1.64 = 12.36. Your answer to question 3 is B. pH=1.64 and pOH=12.36.

Learn more about pH and pOH here:

brainly.com/question/17144456

#SPJ3


Related Questions

Structure and function of cellulose?
ΔH is always positive for a ...........a. endothermic reactionb. exothermic reactionc. spontaneous reaction.d. nonspontaneous reaction.
Convert 50g of calcium carbonate, CaCO3, into moles
How much work is done in lifting a 2kg objext to a height of 1m​
1. Elements combine to form millions ofA. metals.B. mixturesC. compounds.2. The forces that hold atoms together in combinations are calledA. energy bonds.B. nuclear bonds.C. chemical bonds.3. Every electron has aA. neutral charge.B. positive charge.C. negative charge.4. The exact positions of the electrons in an atom cannot be determined becauseelectrons are alwaysA. movingB. sharing.C. changing5. Compared with electrons that are closer to the nucleus, those that are fartheraway haveA. less energyB. more energyC. equal energy

The density for potassium is 0.856 g/cm3. What would be the mass of a 35 cm3 piece of potassium?

Answers

Answer:

30 grams

Explanation:

density = mass / volume => mass = density x volume

mass = 0.856 g/cm³  x  35 cm³ = 29.96 grams ≅ 30 grams 2 sig. figs.  

14) Describe the Cloud Model.

Answers

Electron cloud is an informal term in physics. It is used to describe where electrons are when they go around the nucleus of an atom. The electron cloud model is different from the older Bohr atomic model by Niels Bohr. Bohr talked about electrons orbiting the nucleus.

Determine total H for bonds broken and formed, the overall change in H, and the final answer with units. Is it ENDOthermic or EXOthermic? Reaction:
2H2(g) +O2(g) -> 2H2O^(g)
Given:
H-H 436
O+O 499
O-H 463

Answers

  • E(Bonds broken) = 1371 kJ/mol reaction
  • E(Bonds formed) = 1852 kJ/mol reaction
  • ΔH = -481 kJ/mol.
  • The reaction is exothermic.

Explanation

2 H-H + O=O → 2 H-O-H

There are two moles of H-H bonds and one mole of O=O bonds in one mole of reactants. All of them will break in the reaction. That will absorb

  • E(Bonds broken) = 2 × 436 + 499 = 1371 kJ/mol reaction.
  • ΔH(Breaking bonds) = +1371kJ/mol

Each mole of the reaction will form two moles of water molecules. Each mole of H₂O molecules have two moles O-H bonds. Two moles of the molecule will have four moles of O-H bonds. Forming all those bond will release

  • E(Bonds formed) = 2 × 2 × 463 = 1852kJ/mol reaction.
  • ΔH(Forming bonds) = - 1852 kJ/mol

Heat of the reaction:

  • \Delta H_{\text{rxn}} = \Delta H(\text{Breaking bonds}) + \Delta H(\text{Forming bonds})\n\phantom{ \Delta H_{\text{rxn}}} = +1371 + (-1852) \n\phantom{ \Delta H_{\text{rxn}}} = -481 \; \text{kJ} / \text{mol}

\Delta H_{\text{rxn}} is negative. As a result, the reaction is exothermic.

Joan has four containers. The chart below shows the mass and volume of each of the containers. Two of the containers are filled with solids, one is filled with a liquid, and one is filled with a gas.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, it should be noted that if the containers are compared with an equal average volume, the containers having solids will have larger masses than that containing liquid which will also have a larger mass than that containing gas. This is because solids have there molecules touching each other in compact manner which makes the molecule exert a certain combined force/mass. The molecules of liquid are also close to one another but are not compact like the solids and are hence exerting a lesser force/mass than solids. Gases have free molecules that are far apart and thus are usually the lightest when they occupy the same volume as liquids and solids.

You wish to prepare 100 mL of a 0.100 M solution by dilution of a 1.00 M solution. Which of the following pieces of glassware will you use? A. 100 mL graduated cylinder
B. 100 mL volumetric flask
C. 10 mL volumetric pipet
D. 25 mL volumetric pipet
E. 10 mL graduated pipet
F. 25 mL graduated pipet

Answers

Answer:

C

Explanation:

The volumetric pipet is designed for a specific volume of solution. In this case, a 10 mL of volumetric pipet is required to take exactly 10 mL of the solution 1.00 M and add into a volumetric flask of 100 mL. Then water or solvent(s) can be added to reach the ring of the volumetric flask. This volumetric flask is also a laboratory equipment for precis dilutions beside the volumetric pipet

A sample containing only carbon, hydrogen, and silicon is subjected to elemental analysis. After complete combustion, a 0.7020 g sample of the compound yields 1.4 g of CO2, 0.86 g of H2O, and 0.478 g of SiO2. What is the empirical formula of the compound?

Answers

Answer: The empirical formula of compound is C_4H_(12)Si.

Explanation:

Mass of Sample= 0.702 g

Mass of CO_2 = 1.4 g

Mass of H_2O = 0.86 g

Mass of SiO_2 = 0.478 g  

First we have to calculate moles ofCO_2, H_2O and SiO_2 formed.

1. Moles of CO_2=(1.4g)/(44g/mol)=0.032mol

Now , Moles of carbon == Moles of CO_2 = 0.032

2.  Moles of H_2O=(0.86g)/(18g/mol)=0.048mol​​​

Now , Moles of hydrogen = 2* Moles of H_2O =2* 0.048=0.096mol

3.  Moles of SiO_2=(0.478g)/(60g/mol)=0.008 mol

Now , Moles of silicon = Moles of SiO_2 = 0.008 moles

Therefore, the ratio of number of moles of C : H : Si is  = 0.032 : 0.096 : 0.008

For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C= (0.032)/(0.008)=4

For H =(0.096)/(0.008)=12

For Si=(0.008)/(0.008)=1

Thus, C: H: Si = 4 : 12 : 1

The simplest ratio represent empirical formula.

Hence, the empirical formula of compound is C_4H_(12)Si.