Answer:
19.6 J
Explanation:
The following data were obtained from the question:
Mass (m) of object = 2 Kg
Height (h) = 1 m
Workdone =?
NOTE: Acceleration due to gravity (g) = 9.8 m/s²
Thus, we can obtain the workdone in lifting the object by using the following formula:
Workdone = mgh
Workdone = 2 × 9.8 × 1
Workdone = 19.6 J
Therefore, the workdone in lifting the object to height of 1 m is 19.6 J
a hurricane
a volcanic eruption
a landslide
an earthquake
Answer: I believe the answer is an earthquake.
Explanation: Sorry If I am wrong!
Answer:
earthquake
Explanation:
I took the k12 test
Answer:
Lemon
HCI
Blood
Saliva
Bleach
NaOH
Explanation:
Blood 7.35-7.45
Bleach 12.6
Saliva 6.2-7.6
Lemon 2-3
HCI 3.01
NaOH 13
Answer:
Moles of hydrogen formed = 3.5 moles
Explanation:
Given that:-
Moles of aluminium= 4.0 mol
Moles of hydrogen bromide = 7.0 mol
According to the reaction:-
2 moles of aluminum react with 6 moles of hydrogen bromide
1 mole of aluminum react with 6/2 moles of hydrogen bromide
4 moles of aluminum react with (6/2)*4 moles of hydrogen bromide
Moles of hydrogen bromide = 12 moles
Available moles of hydrogen bromide = 7.0 moles
Limiting reagent is the one which is present in small amount. Thus, hydrogen bromide is limiting reagent. (7.0 < 12)
The formation of the product is governed by the limiting reagent. So,
6 moles of hydrogen bromide on reaction forms 3 moles of hydrogen
1 moles of hydrogen bromide on reaction forms 3/6 moles of hydrogen
7 moles of hydrogen bromide on reaction forms (3/6)*7 moles of hydrogen
Moles of hydrogen formed = 3.5 moles
Answer:
3.5 mol H2, HBr (limiting reactant)
Explanation:
4.0 mol Al × 3 mol H2/ 2 mol Al = 6.0 mol H2
7.0 mol HB ×3 mol H2/ 6mol HBr = 3.5 mol H2
Since 7.0mol of HBr will produce less H2 than 4.0mol of Al, HBr will be the limiting reactant, and the reaction will produce 3.5mol of H2.
Answer:
The polar compounds are soluble in water while non polar are insoluble in water.
Explanation:
Solvent is the that part of solution which is present in large proportion and have ability to dissolve the solute. In simplest form it is something in which other substance get dissolve. The most widely used solvent is water, other examples are toluene, acetone, ethanol, chloroform etc.
Water is called universal solvent because of high polarity all polar substance are dissolve in it. Hydrogen is less electronegative while oxygen is more electronegative and because of difference in electronegativity hydrogen carry the partial positive charge while oxygen carry partial negative charge.
Water create electrostatic interaction with other polar molecules. The negative end of water attract the positive end of polar molecules and positive end of water attract negative end of polar substance and in this way polar substance get dissolve in it.
Example:
when we stir the sodium chloride into water the cation Na⁺ ions are surrounded by the negative end of water i.e oxygen and anion Cl⁻ is surrounded by the positive end of water i.e hydrogen and in this way all salt is get dissolved.
The chemicals that can dissolve in a certain solvent to create a homogenous mixture known as a solution are said to be soluble chemicals. The compounds that are soluble are: , , and .
As per this,
Insoluble:
Thus, these are the classification of the compounds as per their solubility.
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Your question seems incomplete, the prpbable complete question is:
Predict whether the following compounds are soluble or insoluble in water. Soluble Insoluble PbCl2, BaSO4, KNO3, AgNO3, and CuBr2.
Answer:
38.96383282 amu
Explanation:
39.0983 = (40.9618 0.067302) + ( ? (1-0.067302)
39.0983 = 2.756811064 + ( ? 0.932698)
subtract 2.756811064 from both sides
36.34148894 = ( ? 0.932698)
divide both sides by 0.932698
? = 38.96383282 amu
Answer:
38.96383282 amu
Explanation:
39.0983 = (40.9618 0.067302) + ( ? (1-0.067302)
39.0983 = 2.756811064 + ( ? 0.932698)
subtract 2.756811064 from both sides
36.34148894 = ( ? 0.932698)
divide both sides by 0.932698
? = 38.96383282 amu
Moles of any substance is given by the molar mass and the mass. The volume of EDTA required to titrate is 3.16 mL and the volume of zinc required to titrate is 22.8 mL.
Molarity is the property of the solution that gives the concentration of the solute present in the solution.
Given,
Mass of cobalt sulfate = 1.697 gm
The molar mass of cobalt sulfate = 155 g/mol
In the first part, the volume of the aliquot is 25 mL and the molarity is 0.08640 M.
The reaction is shown as:
Co²⁺ + H₄Y → CoH₂Y + 2H⁺
Moles of cobalt: n = 0.001694 ÷ 155 = 0.0000109 moles
In 25 ml aliquot moles of cobalt are, 0.000273 moles.
The volume of EDTA solution is calculated as:
V = moles ÷ Molarity
= 0.000273 mole ÷ 0.0864 mol/ L
= 3.16 mL
Hence, 3.16 mL of EDTA is required.
For the second part, moles of EDTA are calculated as:
n = 0.008640 × 0.050 = 4.32 ×10⁻⁴
In a 25 mL, sample moles of EDTA are 2.16 × 10⁻⁴ moles.
Excess moles of EDTA in the solution:
0.000432 - 0.000216 = 0.000216 moles
The volume of EDTA is calculated as:
V = 0.000216 ÷ 0.009450
= 0.0228 L
Hence, 22.8 mL of zinc is required.
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Answer:
the answer is in the screenshot
Explanation:
hope this helps