1. Elements combine to form millions ofA. metals.
B. mixtures
C. compounds.
2. The forces that hold atoms together in combinations are called
A. energy bonds.
B. nuclear bonds.
C. chemical bonds.
3. Every electron has a
A. neutral charge.
B. positive charge.
C. negative charge.
4. The exact positions of the electrons in an atom cannot be determined because
electrons are always
A. moving
B. sharing.
C. changing
5. Compared with electrons that are closer to the nucleus, those that are farther
away have
A. less energy
B. more energy
C. equal energy
Answers
question no 1 answer is compounds
Final answer:
Elements combine to form millions of compounds. The force holding atoms together in these combinations are chemical bonds. Each electron has a negative charge, electrons are always moving, and have more energy the farther they are from the nucleus.
Explanation:
The elements can combine in many ways to create compounds, which amount to millions. When atoms connect or adhere to each other to shape those compounds, it happens through chemical bonds. In an atom, each electron has a negative charge, a characteristic that's vital for the creation of chemical bonds. Electrons are in constant movement, which means we cannot exactly determine their positions. As for the energy level of these electrons, those farther away from the nucleus have, in general, more energy than the ones located closer to the nucleus.
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questions with regards to this reaction.
a) Write the molecular equation for this reaction by
Translating the two reactants into their chemical formulae.
Predict the products.
Label all the states.
Balance the reaction.
Answers
Answer:
2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)
Explanation:
Aqueous solutions of iron(III) bromide and ammonium carbonate react. This is a double displacement reaction that gives place to ammonium bromide and iron (III) carbonate. Iron (III) carbonate is insoluble so it precipitates. The corresponding molecular equation is:
2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)
Answers
Answer:
H2O (water)
N2 (nitrogen)
O3 (ozone)
CaO (calcium oxide)
Explanation:
HOPE IT HELPS
Answers
According to the valence bond theory the triple bond in ethyne consists of one sigma bond and two pi bonds.
Explanation:
Atomic number of carbon is 6. The ground state electronic configuration of carbon is as follow,
1s², 2s², 2p²
And the excited state electronic configuration of carbon is as follow,
1s², 2s¹, 2px¹, 2py¹, 2pz¹
In ethyne the 2s¹ orbital and 2px¹ orbitals having unpaired electrons form sigma bonds by head to head overlapping with orbitals of hydrogen atom and carbon atom. The remaining 2py¹ and 2pz¹ orbitals of both carbons overlap perpendicular to the existing sigma bond resulting in the formation of two pi bonds.
Answers
Answer:
The correct answer is 5.6 × 10⁻²³ M.
Explanation:
As a highly soluble salt, KBr dissolves easily in water, while Hg₂Br₂ is very less soluble in comparison to KBr.
Let the solubility of Hg₂Br₂ is S mol per liter.
Therefore,
KBr (s) (1.0 M) ⇒ K⁺ (aq) (1M) + Br⁻ (aq) (1M)
Hg₂Br₂ (s) (1-S) ⇔ Hg₂⁺ (aq) (S) + 2Br⁻ (aq) (2S)
Net [Br-] = (2S + 1) M
Ksp = S (2S + 1)²
Ksp = S (4S² + 1 + 4S)
Ksp = 4S³ + S + 4S²
As the solubility is extremely less, therefore, we can ignore S² and S³. Now,
Ksp = S = 5.6 × 10⁻²³ M
Hence, the solubility of Hg₂Br₂ is 5.6 × 10⁻²³ M.
Answers
Answer:
Chloroform.
Explanation:
Given,
Solvent requires 1g of compound per 100 mL
For water,
= 1g/47ml
= 2.1
For Chloroform,
= 1 g/8.1 mL
= 12.345679
For Diethyl ether,
= 1 g/370 mL
= 0.27
For Benzene,
= 1 g/86 mL
= 1.2
Partition coefficients:
Water = -
chloroform = 5.9
Diethyl = .13
Benzene = .57
The solvent chloroform would be chosen for drawing out the compound out of an aqueous solution as it has the maximum solubility.
Final answer:
The solubility of a compound in different solvents will determine its concentration in each solvent. The partition coefficient represents the relative solubility of a compound in two immiscible solvents. Chloroform would be the best choice to extract the compound from an aqueous solution.
Explanation:
The solubility of a compound is usually expressed as grams of solute per 100 mL of solvent. To calculate the solubility, you can use the following formula:
Solubility (g/100 mL) = (mass of solute / volume of solvent) * 100
Using this formula, the solubility of the compound in water is 47 g/100 mL, in chloroform is 97.53 g/100 mL, in diethyl ether is 2.70 g/100 mL, and in benzene is 1.16 g/100 mL.
The partition coefficient is a measure of the compound's solubility in two immiscible solvents. To calculate it, divide the solubility of the compound in one solvent by its solubility in another solvent. For example, the partition coefficient between chloroform and water would be:
Partition coefficient = Solubility in chloroform / Solubility in water = 97.53 g/100 mL / 47 g/100 mL = 2.07
The larger the partition coefficient, the more soluble the compound is in the first solvent compared to the second solvent. Based on the partition coefficients, chloroform would be the best choice to extract the compound from an aqueous solution.
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[Ar]3d^5
Check all that apply.
A- Fe2+
B- Fe3+
C- Mn2+
D- V+
E- Sc2+
Answers
Answer:
Explanation:
Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom. The electrons are filled according to Afbau's rule in order of increasing energies.
The electronic configuration for given elements is as follows:
Final answer:
The ions Fe2+ and Mn2+ have the ground-state electron configuration [Ar]3d^5.
Explanation:
The ground-state electron configuration [Ar]3d^5 indicates a level of electrons in 3d subshell after the Argon core electron configuration. Now, iron (Fe) has a base atomic configuration of [Ar]3d^6 4s2. When it loses 2 electrons (to form Fe2+), it tends to lose from both the 3d and the 4s sublevels, giving [Ar]3d^5 (which is our required configuration).
However, it's also important to consider Manganese (Mn), which has a base configuration of [Ar]3d^5 4s2. It usually loses 2 electrons from the 4s sublevel first when it forms Mn2+ which results in a configuration [Ar]3d^5.
So, the two ions with the electron configuration [Ar]3d^5 are Fe2+ and Mn2+.
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