If one body is positively charged and another body is negatively charged, free electrons tend to A. move from the negatively charged body to the positively charged body.
B. remain in the negatively charged body.
C. move from the positively charged body to the negatively charged body.
D. remain in the positively charged body.

Answer:

Explanation:

To determine the volume of the stock solution required to prepare 3.50 L of 0.200 M hydro chloric acid, we can use the formula:

M1V1 = M2V2

where:

M1 = concentration of the stock solution

V1 = volume of the stock solution

M2 = desired concentration of the diluted solution

V2 = desired volume of the diluted solution

Let's substitute the given values into the formula:

M1 = 12.0 M

V1 = ?

M2 = 0.200 M

V2 = 3.50 L

Now we can solve for V1:

12.0 M x V1 = 0.200 M x 3.50 L

V1 = (0.200 M x 3.50 L) / 12.0 M

V1 = 0.0583 L

To convert the volume from liters to milliliters, we multiply by 1000:

V1 = 0.0583 L x 1000 mL/L

V1 = 58.3 mL

Therefore, the volume of the stock solution required is 58.3 mL.

So, the correct answer is d. 58.3 mL.

To determine the volume of the stock solution required, we can use the formula:

Molarity1 x Volume1 = Molarity2 x Volume2

Where Molarity1 and Volume1 represent the initial concentration and volume, and Molarity2 and Volume2 represent the final concentration and volume.

Given:

Molarity1 = 12.0 M

Volume1 = ?

Molarity2 = 0.200 M

Volume2 = 3.50 L

Plugging in the values into the formula, we have:

12.0 M x Volume1 = 0.200 M x 3.50 L

Simplifying the equation, we can solve for Volume1:

Volume1 = (0.200 M x 3.50 L) / 12.0 M

Volume1 ≈ 0.0583 L

To convert this to milliliters, we multiply by 1000:

Volume1 ≈ 58.3 mL

Therefore, the volume of the stock solution required is approximately 58.3 mL.

The closest answer option is d. 58.3 mL.

I hope this explanation helps! Let me know if you have any further questions.

Answer:

c.filtration is the answer