The reaction of p-aminophenol with one mole of acetyl chloride in the presence of pyridine results in the formation of an amide compound.
The reaction of p-aminophenol with one mole of acetyl chloride in the presence of pyridine leads to the formation of an amide compound. This reaction is known as acylation, where the acetyl chloride acts as the acylating agent and reacts with the amino group of p-aminophenol to form an amide bond.
#SPJ11
c. stability
b. nucleus size
d. atomic mass
-Carbonic Acid
-Hydrogen Gas
-Atom
-Proton
-Sodium Chloride
-Triglyceride
-Electron
-Protein
-Amino Acid
b. The different kinds of compounds included within the chemical formula
c. The types of molecules present in a formula
d. The correct amounts of substances to mix together to make a formula
2) 0.000023
3) 101,000
4) 0.010
5) 45.01
6) 1,000,000
7) 0.00671
8) 4.50
The question asked about converting normal numbers into scientific notation. The answer provided the eight scientific notation equivalents for each of the numbers provided in the question, explaining the process of calculating them.
To write numbers in scientific notation, we have to express them in the form of a x 10^n, where 1 <= a < 10 and n represents the number of places the decimal place has been moved. Let's proceed with each given number:
#SPJ2
The balanced chemical reaction is:
2Al2O3 = 4Al +3 O2
We are given the amount of the reactant. This will be the starting point of our calculations.
26.5 mol Al2O3 ( 3 mol O2 / 2 mol Al2O3 ) = 39.75 mol O2 needed
Thus, 0.014 mol of I2 is needed to form the given amount of NI3.
the balanced chemical equation for the decomposition of Al₂O₃ is as follows
2Al₂O₃ --> 4Al + 3O₂
stoichiometry of Al₂O₃ to O₂ is 2:3
when 2 mol of Al₂O₃ decomposes - 3 mol of O₂ are formed
therefore when 26.5 mol of Al₂O₃ decomposes - 3/2 x 26.5 mol = 39.75 mol
the number of moles of O₂ formed are 39.75 mol