Answer: Element
Explanation: hope this helps :3
Fluorine
Explanation:
F- has the lowest ionisation energy
B. For most of its life cycle, star A appeared substantially brighter than star B from earth
C. For most of its life cycle, star B appeared substantially brighter than star A from earth
Only five supernovae have ever been documented as being visible to the unaided eye, with two of those believed to be core-collapse supernovae. Thus, option B is correct.
Iron atoms are compressed so closely together that the nuclei's repelling forces cause the squeezed core to recoil, which causes the star to go supernova and generate a massive, superheated shock wave.
A supernova explosion takes place in a star over the course of just 100 seconds. A star that experiences a supernova explosion dies and leaves behind a neutron star or a black hole as a remnant.
The largest explosion that mankind have yet witnessed is a supernova. Each explosion is the incredibly bright, incredibly potent explosion of a star. The largest explosion that mankind have yet witnessed is a supernova.
Therefore, For most of its life cycle, star A appeared substantially brighter than star B from earth
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A controlled experiment is an experimental setup designed to test the hypotheses. It has one or more conditions (independent variables) and measures (dependent variables). It is necessary to change more than one variable, but all os the experimental conditions will be controlled so that only the variables being examined change and the amount or way of change is measured.
Radioactive elements are the unstable nuclei of the atoms that release energy and radiation. The atomic number remains the same in case of the gamma radiation.
Gamma radiations are the particles that are released when the unstable atom undergoes decay and emits charged particles. These rays have no effect on the atomic mass and number of the atom.
These rays only emitenergy whereas alpha and beta decay produces energy and newparticle. An excited nucleus emits energy in the case of gamma decay that is unlike the other two decays.
Therefore, there is no change in the atomicnumber in gamma decay.
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Answer: It actually remains the same.
Explanation: Gamma radiation does not affect the atomic number or the atomic mass.
Answer:
1.74845
Explanation:
We have the following reaction:
I2 + H2 => 2 HI
Now, the constant Kc, has the following formula:
Kc = [C] ^ c * [D] ^ d / [A] ^ a * [B] ^ b
In this case I2 is A, H2 is B and C is HI
We know that the values are:
H2 = 1 × 10 ^ -3 at 448 ° C
I2 = 2 × 10 ^ -3 at 448 ° C
HI = 1.87 × 10 ^ -3 at 448 ° C
Replacing:
Kc = [1.87 × 10 ^ -3] ^ 2 / {[2 × 10 ^ -3] ^ 1 * [1 × 10 ^ -3] ^ 1}
Kc = 1.87 ^ 2/2 * 1
Kc = 1.74845
Which means that at 448 ° C, Kc is equal to 1.74845
Answer:
Explanation:
[H2] = 10^-3
[I2] = 2*10^-3
[HI] = 0
in equilbiirum
[H2] = 10^-3 - x
[I2] = 2*10^-3 -x
[HI] = 0 + 2x
and we know
[HI] = 0 + 2x = 1.87*10^-3
x = ( 1.87*10^-3)/2 = 0.000935
then
[H2] = 10^-3 - 0.000935 = 0.000065
[I2] = 2*10^-3 -0.000935 = 0.001065
H₂ + I ⇄ 2 HI
Initially 1 × 10⁻³ 2 × 10⁻³
Change -9.35 × 10⁻⁴ -9.35 × 10⁻⁴ +1.87 × 10⁻³
At equil 6.5 × 10⁻⁵ 1.06 5 × 10⁻³ 1.87 × 10⁻³
HI increase by 1.87 × 10⁻³M