(1) C6H12O6 (3) CaCl2
(2) CH3OH (4) CCl4
The correct answer is 9.6h.
As you know, a radioactive isotope's nuclear half-life tells you exactly how much time must pass in order for an initial sample of this isotope to be halved.
Using the formula , A = Ao.
where , A- final mass after decay
Ao - initial mass
n - the number of half-lives that pass in the given period of time
Now, putting all the values, we get
1.3 × mg = 0.050 mg ×
Take the natural log of both sides of the equation to get,
㏑ = ㏑
㏑ = n. ln
n = 1.6
Since n represents the number of half-lives that pass in a given period of time, you can say that
t= 1.6 × 6 h
t = 9.6h
Hence, it will take 9.6 h until the radioactive isotope decays.
Learn more about radioactive isotope andhalf life here:-
#SPJ1
Using the formula for radioactive decay and the provided half-life of technetium-99m, it can be calculated that it takes approximately 28.5 hours for 0.050 mg of technetium-99m to decay to a quantity of 1.3 x 10^-2 mg.
The decay of a radioactive isotope is an exponential process based on the half-life, which is, in turn, constant for any given isotope. The general formula for the remaining quantity of a radioactive isotope after a given time is given by: N = N0 (0.5) ^(t/t1/2), where (N0) is the initial amount, (N) is the remaining amount, (t) is time, and (t1/2) is the half-life of the isotope. In this case, we are given the initial quantity (N0 = 0.050 mg), the remaining quantity (N = 1.3 x 10^-2 mg), and the half-life (t1/2 = 6.0 hours).
We can solve for time (t) in the equation: N = N0 (0.5) ^(t/t1/2). Plugging in the values, we get 1.3 x 10^-2 = 0.050 x (0.5)^(t/6), and solving for t, we find that it takes approximately 28.5 hours for the technetium-99m to decay to 1.3 x 10^-2 mg.
#SPJ11
metal and nonmetal
metalloid and nonmetal
two metals
Answer: The correct answer is metal and non-metal.
Explanation:
Elements are mainly divided into 3 classes in the periodic table.
1.) Metals: The element which lie on the left side of the periodic table are mainly metals. These elements loose electron easily and form positively charged species. These elements are present in the highest proportion in the periodic table.
2.) Non-metals: The elements which lie on the right side of the periodic table are considered as non-metals. These elements gain electrons easily and form negatively charged species.
3.) Metalloids: These lie between metals and non-metals and show the properties of both metals and non-metals.
Copper lie in the period 4 and group 11 of the periodic table and it can easily loose electron and hence, it is considered as a metal.
Chlorine lie in the period 3 and group 17 of the periodic table and it can easily gain electron and hence, considered as a non-metal.
Therefore, the correct answer is metal and non-metal.
(a) Balance the above redox reaction.
(b) Determine the concentration of H2O2 solution in molarity if 10.00 mL of this solution requires 20.00 mL of 1.5 M MnO4− for a complete reaction.
Answer:
A)
B) 7.5 molar
Explanation:
A)Reduction
Oxidation
Multiplying the oxidation reaction by 5/2 and adding it to the reduction equation:
+
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B) 10 ml = 0.01 L
20 ml = 0.02 L
mol of MnO4− = molarity*volume = 1.5*0.02 = 0.03
1 mol of MnO4− reacts with 5/2 mol of H2O2, then:
mol of H2O2 = 0.03*5/2 = 0.075
molarity = mol/volume = 0.075/0.01 = 7.5 molar
Answer:
The reaction would be 1500n (equal reaction)
Explanation:
This can be explained by Newton's third law of motion which states that for every action (force), there is an opposite and equal reaction. In other words, when two objects or people come in contact, the magnitude of force which they exert on each other is equal and they both feel an equal reaction force.
It doesn't matter whether one of the colliding bodies is of bigger mass than the other. This Newton's third law of motion is also known as the law of action and reaction.