Answer:
The answer is True
Explanation:
Answer:
true!!!!!
Explanation:
Answer:
The correct option is: D. A small lever in a relay switch
Explanation:
Armature is a constituting part of an electric machine, that can be used as a stationary or rotating part. It is a conductor or a conducting coil that carries alternating current and can generate electromotive force.
In a solenoid, the movable steel or iron part that functions as a switch or relay is also termed as the armature.
B.) If the solid is not conductive, the bonds are covalent.
C.) If the solid is conductive, the bonds are metallic.
D.) If the solid is not conductive, the bonds are metallic.
Answer is: C.) If the solid is conductive, the bonds are metallic.
1) Substances with ionic bond conduct an electric current in liquid, but not in solid state, because in liquids ions are mobile, contrary to solids where ions are fixed.
2) Substances with covalent bond not conduct an electric current in liquid and solid state, because they not have free ions or electrons.
3) Substances with metallic bond conduct an electric current in liquid and solid state, because they have mobile electrons. Most metals have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.
Answer:C.) If the solid is conductive, the bonds are metallic.
Explanation:
Answer:
approximately 4.8 grams of oxygen gas is formed.
Explanation:
To determine the amount of oxygen (O2) formed when 12.26 grams of potassium chlorate (KClO3) is heated, we need to consider the chemical reaction that occurs during this process. When KClO3 is heated, it decomposes into potassium chloride (KCl) and oxygen gas (O2).
The balanced chemical equation for this reaction is:
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
From the equation, we can see that 2 moles of KClO3 produce 3 moles of O2.
Calculate the molar mass of KClO3:
K: 39.10 g/mol
Cl: 35.45 g/mol
O: 16.00 g/mol
Molar mass of KClO3 = (39.10 + 35.45 + 3 * 16.00) g/mol = 122.55 g/mol
Calculate the number of moles of KClO3 in 12.26 grams:
Moles of KClO3 = (12.26 g) / (122.55 g/mol) = 0.1 moles
Now, we can determine the number of moles of O2 produced using the mole ratio from the balanced equation:
Moles of O2 = (0.1 moles of KClO3) * (3 moles of O2 / 2 moles of KClO3) = 0.15 moles
Finally, convert moles of O2 to grams:
Mass of O2 = (0.15 moles) * (32.00 g/mol for O2) = 4.8 grams
So, when 12.26 grams of KClO3 is heated, approximately 4.8 grams of oxygen gas is formed.