Answer:
Yes; new substances formed, as evidenced by the color changes and bubbles. Some signs of a chemical change are a change in color and the formation of bubbles. The five conditions of chemical change: color chage, formation of a precipitate, formation of a gas, odor change, temperature change
The alpha decay of Radon-198 produces alpha particle and ¹⁹⁴₈₄Po.
Alpha decay is a type of radioactive disintegration in which some unstable atomic nuclei spontaneously expel an alpha particle to dissipate excess energy.
Alpha decay of Radon-198 is shown as:
¹⁹⁸₈₆Rn → ⁴₂He + ¹⁹⁴₈₄Po
In the above decay from the parent nuclei, daughter nuclei (¹⁹⁴₈₄Po) and alpha particle (⁴₂He) is produced.
Hence daughter nuclei of the alpha decay of Radon-198 is ¹⁹⁴₈₄Po.
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(3) energy, charge and mass
(4) energy, charge and volume
A. ice floating in a glass of water
B. vapor rising from a hot cup of tea
C. cooled magma sinking in a lava flow
D. a hot air balloon falling as the gas inside cools
Using Gay-Lussac's Law, we calculate that when the temperature of a gas increases from 320 K to 450 K, the pressure of the gas will increase from 1.5 atm to 2.1 atm, assuming the volume and the amount of gas remain constant.
To answer the question, we need to use the concept in physics called Gay-Lussac's Law. This law states that the pressure of a given amount of gas held at a constant volume is directly proportional to the Kelvin temperature. It's also important to remember that when we're dealing with gases, temperatures have to be in Kelvin for our calculations to work.
Given that, we know that the initial pressure (P1) is 1.5 atm, the initial temperature (T1) is 320K, and the final temperature (T2) is 450K. We want to find the final pressure (P2). According to Gay-Lussac's law, this can be calculated using the following equation: P1/T1 = P2/T2.
Thus, P2 = P1 * T2 / T1 = 1.5 atm * 450K / 320K = 2.1 atm.
So, the gas pressure will be 2.1 atm when the temperature increases from 320 K to 450 K, assuming that the volume and the amount of gas remain constant.
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