Which net represents the pyramid below

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

its D

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How do i figure out 120% of 25

Answers

120% of 25 = 1.20 × 25 = 30, so your answer is 30.

STEPS:
1) You place a decimal 2 digits from the end of the percent (or number)
2) You multiply the two numbers together
3) You find your answer

During the first quarter of the year, 351,875 people downloaded an an app for their smartphones. During the second quarter of the year, 101,949 fewer people downloaded the app than the first quarter. How many downloads occurred during the two quarters of the year?

Answers

351,875 - 101,949 = 249,926

351,875 + 249,926 = 601,801

If you subtract 351,875 from 101,949 you will come up with 249,926.

A parallelogram has an area of 396 square centimeters and a height of 18 centimeters.What is the length of the base of the parallelogram?

Answers

The length of the base of the parallelogram is 22 cm.

Given:
Area = 396 cm²
height = 18 cm

Area of a parallelogram is computed by multiplying its base to its height.

A = bh
396 cm² = b * 18cm
396 cm²/18cm = b
22 cm = b

David invested $1000.ppm what would that money grow to the 18 months at 5.5% interest rate?

Answers

David invested $1000. Let's solve for the amount of money to grow to the 18 months at 5.5% interest rate?
Let's assume that this 5.5% interest is per month.
=> 1 000 dollars * 0.055 = 55 dollars per month
=> 55 * 18 months = 990 dollars in 18 months.

Abner went to dinner, and spent 33.60 this included 20% tax. How much did dinner cost before the tax?

Answers

- - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - -

➷ Figure out the original multiplier:

1 + 0.2 = 1.2

Since we are trying to find the original cost, divide the cost by this value

33.60/1.2 = 28.

Dinner cost $28 before the tax.

➶Hope This Helps You!

➶Good Luck :)

➶Have A Great Day ^-^

↬ Hannah ♡

Solve x+1>10, x+11>20, and x+21>30

Answers

x+1>10
x>10-1
x>9

x+11>20
x>20-11
x>9

x+21>30
x>30-21
x>9

$\framebox[1.1\width]{Godspeed!} \par$

$a) \n x+1>10 \n x>10-1 \n x>9 \n \n \n b) \n x+11>20 \n x>20-11 \n x>9 \n \n \n c) \n x+21>30 \n x>30-21 \n x>9 \n \n \n \framebox[1.1\width]{Good Luck !} \par$