12) Mrs. Benton is making food baskets for the homeless. There are 60 cans of beans and 48 cans of tuna available to be divided equally among the baskets. What is the greatest number of baskets that Mrs. Benton can make

Answers

Answer 1
Answer:

Answer:

Maximum no. of baskets which Mrs. Benton can make is , 12.

Step-by-step explanation:

According to the question, the greatest number of basket Mrs. Benton can make is,  GCD (Greatest Common Divisor) of 60 and 48.

Now,

60 = 2 * 2 * 3 * 5

and . 48 = 2 * 2 * * 2 * \2 * 3

So, the GCD of 60 and 48 is,

2 * 2 * 3 = 12

So, each basket will have,

\frac {60}{12} = 5 cans of beans and

\frac {48}{12} = 4 cans of tuna


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What does b−2≥−1 equal ????

Answers

b - 2 > -1

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A club is going to raise money by printing calendars with photos of the community. The cost of printing the calendars is $5.50 per calendar. The photographer also charges a one-time cost of $200 for taking the photos. The club has $1500 to cover the initial costs of the calendar. Create an equation that represents the number of calendars the club can print. Use the variable n for the number of calendars (You do not need to solve the equation).

Answers

Answer:

The total cost to print n calendars is the sum of the cost of printing each calendar and the one-time cost for taking the photos:

Total cost = (Cost per calendar * Number of calendars) + One-time cost for photos

Given that the cost per calendar is $5.50 and the one-time cost for photos is $200, the equation can be written as:

Total cost = 5.50n + 200

Now, we know that the club has $1500 to cover the initial costs of the calendars. Therefore, the equation can be set equal to $1500:

5.50n + 200 = 1500

So, the equation representing the number of calendars the club can print is 5.50n + 200 = 1500, where n is the number of calendars.

Step-by-step explanation:

1500 so yes its the easy way

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Answers

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A number, rounded to the nearest thousand is 47,000. Which number could be the number that was rounded?

Answers

Answer:

46,900

Step-by-step explanation:

The number can be any number that has 46 in the thousand place and a number that is 5 or above in the hundred place. After that the numbers can be any number. Since you round up from 5 or above the digit 6 will round up to 7 in the thousand place

(2y-1)(4y-3) What is the answer to this?

Answers

(2y-1)(4y-3)=2y\cdot4y+2y\cdot(-3)-1\cdot4y-1\cdot(-3)\n\n=8y^2-6y-4y+3=8y^2-10y+3
8y^2-10y+3
FOIL
2yx4y+2yx-3+-1x4y+-1x-3