Karen is seven years older than suzanne.Four years ago,karen was twice as old as suzanne was.How are they now?

Answers

Answer 1

Answer: $K-Karen\ age\nS-Suzanne\ age\nK-4-Karen\ age\ 4\ years\ ago\nS-4-Suzanne\ age\ 4\ years\ ago\n\n \left\{\begin{array}{ccc}K=S+7\nK-4=2(S-4)\end{array}\right\n\left\{\begin{array}{ccc}K=S+7&(1)\nK-4=2S-8&(2)\end{array}\right\n\nsubtitute\ (1)\ to\ (2):\n\n(S+7)-4=2S-8\nS+7-4=2S-8\nS+3=2S-8\ \ \ \ |subtract\ 3\ from\ both\ sides\nS=2S-11\ \ \ |subtract\ 2S\ from\ both\ sides\n-S=-11\n\boxed{S=11}$

$Put\ the\ value\ of\ S\ to\ (1):\n\nK=11+7\n\boxed{K=18}\n\n\left\{\begin{array}{ccc}K=18\nS=11\end{array}\right\n\nAnswer:\ Karen\ does\ 18\ years\ and\ Susanne\ does\ 11\ years.$

Answer 2

Answer: karen age=k
suzanne age=s

karen (k) is (=) 7 years older (+7) than suzanne(s)
k=7+s

four year ago means
s-4 and k-4

four years ago (-4 to all) karen (k) was (=) twice (2 times) suzzane (s)
k-4=2(s-4)
distribute
k-4=2s-8
add 4 to both sides
k=2s-4
we know that k=7+s so subsitute 7+s for k
7+s=2s-4
add 4 to both sides
11+s=2s
subtract s from both sides
11=s

suzanne=11
subsitute 11 for s in k=s+7

k=7+11
k=18

karen=18
suzanne=11

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Answers

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The sum of two consecutive interferes is at least 7 (n and n + 1 represent two interferes

Answers

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Answers

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Answers

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Four times a number increased by 3 is the same as twice the number increased by 9? I'm horrible at these

Answers

The question says:
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so now you need to find x
first you should add -2(x) on both sides of the equation and then add -3 on both sides:
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I hope this is helpful
have a nice day

Four times a number (we are gonna make that be "x") increased by 3 would be 4x+3 it says it is the same as (means it is equal to) twice the number (2x) increased by 9 (+9) so the full equation would be 4x+3=2x+9
You have to solve for the number (x).
4x+3=2x+9
-2x -2x (Have to get the x's to one side)
2x+3=9
-3 -3 (you have to get the numbers on one side too)
2x=6
/2 /2 (to get x alone)
X=3 (the number is 3)

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