PHYSICS COLLEGE

Which lists mixtures, in order, from the smallest particles to the largest particles?O solution, colloid, suspension
solution, suspension, colloid
O suspension, colloid, solution
O suspension, solution, colloid

Answers

Answer 1
Answer:

The order of mixtures according to their particle size from smallest to the largest is: solution< colloid< suspension. So, the first option is correct.

What is meant by solvent and solute in a mixture ?

Solvent is defined as the substance in which the solute particles dissolve and forms a mixture. Solute is defined as the particles that get dissolved in the solvent to form the mixture.

Here,

The particles of the solutions, colloids and suspension varies according to their size and the type of mixture they comes under.

Colloid is a heterogenous mixture, that means it has a non-uniform composition of particles. In colloid, the particles have an intermediate size between 1 nm to 1000 nm which is the size range between that of solution and suspension.

Solution is a homogenous mixture in which the particles have a diameter of less than 1 nm. The size of the particles in solution is the smallest when compared to that of colloid and suspension.

Suspension is a homogenous mixture in which the size of the particles is larger than 10000 nm. The particles of suspension are the largest among the particles of colloid and solution.

Hence,

The order of mixtures according to their particle size from smallest to the largest is: solution< colloid< suspension.

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Answer 2
Answer:

Answer:

A or 1

Explanation:

solution, colloid, suspension

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What does a planet need in order to retain an atmosphere? How does an atmosphere affect the surface of a planet and the ability of life to exist?

Answers

Answer:

Explained

Explanation:

In order to retain atmosphere a planet needs to have gravity. A gravity sufficient enough to create a dense atmosphere around it, so that it can retain heat coming from sun. Mars has shallow atmosphere as its gravity is only 40% of the Earth's gravity. Venus is somewhat similar to Earth but due to green house effect its temperature is very high. Atmosphere has a huge impact on the planets ability to sustain life. Presence of certain kind gases make the atmosphere poisnous for life. The atmosphere should be such that it allows water to remain in liquid form and maintain an optimum temperature suitable for life.

Garza travels at a speed of 5 m/s. How long will it take him to travel 640 m?

Answers

Answer:

128 s

Explanation:

The distance, speed and time are related as;

Distance=Speed* Time

Given that the speed = 5 m/s

Distance = 640 m

Time = ?

So,

Distance=Speed* Time

640\ m=5\ m/s* Time

Time=\frac {640\ m}{5\ m/s}=128\ s

Thus, Garza takes 128 s to travel 640 m at 5 m/s speed.

Consider as a system the Sun with Saturn in a circular orbit around it. Find the magnitude of the change in the velocity of the Sun relative to the center of mass of the system during the time Saturn completes half an orbit. Assume the mass of the Sun is 5.68 x10^29 kg, the mass of Saturn is 5.68 x10^26 kg, its period is 9.29 x10^8 s, and the radius of its orbit is 1.43 x 10^12 m. Ignore the influence of other celestial objects.?

Answers

Answer:

v_(su) = 19.44 m/s

Explanation:

m_(su)=5.68x10^(29)kg\nm_(sa)=5.68x10^(26)kg

T=9.29x10^8\nr_(o)=1.43x10^(12)

If the sun considered as x=0 on the axis to put the center of the mass as a:

m_(su)*r_(o)=(m_(sa)+m_(su))*r_(1)

solve to r1

r_1=(m_(sa)*r_(o))/(m_(sa)+m_(su))=(5.68x10^(26)*1.43x10^(12))/(5.68x10^(26)+5.68x10^(26))

r_1=1.428x10^9m

Now convert to coordinates centered on the center of mass.  call the new coordinates x' and y' (we won't need y').  Now since in the sun centered coordinates the angular momentum was  

L = (m_(sa)*2*pi*r_1^2)/(T)

where T = orbital period

then L'(x',y') = L(x) by conservation of angular momentum.  So that means

L_(sun)=(m_(sa)*2*\pi *( 2r_(o)*r_1 -r_1^2))/(T)

Since

L_(su)= m_(su)*v_(su)*r_1

then

v_(su)=(m_(sa)*2*pi*(2r_(o)*r_(1)-r_(1)^2))/(T*m_(sa)*r_1)

v_(su) = 19.44 m/s

Final answer:

In a two-body system such as the Sun-Saturn system, both bodies orbit around their mutual center of mass, or barycenter. Given the Sun's significantly larger mass, this barycenter is near the center of the Sun, and hence the Sun's change in velocity relative to the center of mass of the system as Saturn completes half an orbit is effectively zero.

Explanation:

The problem here is asking for the change in velocity of the Sun relative to the center of mass of the Sun-Saturn system as Saturn completes half an orbit. This is a situation involving orbital physics and center of mass systems.

However, in an isolated two-body orbit system like this, the center of mass does not change velocity - it would remain constant, not unless acted upon by an outside force, which the problem instructs us to ignore.

Saturn and the Sun both orbit around their common center of mass (their barycenter). Given that the Sun is immensely more massive than Saturn, this center of mass is located very close to the center of the Sun.

So, while the Sun does indeed move a little due to Saturn's influence, the change in velocity of Sun relative to the center of mass of the system during the time Saturn completes half an orbit, for all intents and purposes, is zero.

This is especially true unless the problem specifically mentions that the Sun is initially at rest with respect to the center of mass. In any other case, the relative velocity remains constant and hence the change is zero.

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Suppose that a solid ball, a solid disk, and a hoop all have the same mass and the same radius. Each object is set rolling without slipping up an incline with the same initial linear (translational) speed. Which object goes farthest up the incline?

Answers

Final answer:

Given the same initial linear speed, a solid ball, solid disk, and hoop will expend energy on both rotation and translation. The solid ball, having the lowest moment of inertia, uses the most energy for translation and, therefore, will travel the highest up an incline.

Explanation:

In the context of this problem related to physics, the deciding factor is the distribution of mass, which influences each object's moment of inertia. Objects set to roll tend to use energy in two ways: translation (moving along the incline) and rotation (spinning about their center). Moment of inertia essentially measures how much of the object's energy goes towards rotation.

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Patricia places 1500g of fruit on a scale compressing it by 0.02m. What is the force constant of the spring on the scale. Hint: you need 2 equations to solve this.

Answers

Answer:

The force constant of the spring is 735 N/m.    

Explanation:

It is given that,

Mass of fruit, m = 1500 g = 1.5 kg

Compression in the scale, x = 0.02 m

We need to find the force constant of the spring on the scale. The force acting on the scale is given by using Hooke's law. So,

F=-kx

Also, F = mg

mg=kx

k is force constant

k=(mg)/(x)\n\nk=(1.5* 9.8)/(0.02)\n\nk=735\ N/m

So, the force constant of the spring is 735 N/m.

Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 162 cm , but its circumference is decreasing at a constant rate of 14.0 cm/s due to a tangential pull on the wire. The loop is in a constant uniform magnetic field of magnitude 0.500 T , which is oriented perpendicular to the plane of the loop. Assume that you are facing the loop and that the magnetic field points into the loop. Find the magnitude of the emf EMF induced in the loop after exactly time 8.00s has passed since the circumference of the loop started to decrease.

Answers

Answer:

0.00124 V

Explanation:

Parameters given:

Initial circumference = 162 cm

Rate of decrease of circumference = 14 cm/s

Magnetic field, B = 0.5 T

Time, t = 8 secs

The magnitude of the EMF induced in the loop is given as:

V = (-NBA) / t

Where N = number of turns = 1

B = magnetic field

A = area of loop

t = time taken

First, we need to find the area of the loop.

To do this, we will find the radius after the loop circumference has decreased for 8 secs.

The rate of decrease of the circumference is 14 cm/s and 8 secs has passed, which means after 8 secs, it has decreased by:

14 * 8 = 112 cm

The new circumference is:

162 - 112 = 50 cm = 0.5 m

To get radius:

C = 2 * pi * r

r = C / (2 * pi)

r = 0.5 / (2 * 3.142)

r = 0.0796 m

The area is:

A = pi * r²

A = 3.142 * 0.0796²

A = 0.0199 m²

Therefore, the EMF induced is:

V = (-1 * 0.5 * 0.0199) / 8

V = -0.00124V

This is the EMF induced in the coil.

The magnitude is |-0.00124| V = 0.00124 V.

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