Which is not a product of the fractional distillation of petroleum?A) Gasoline
B) Jet Fuel
C) steel

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Answer 1

Answer: Answer:
Option-C, STEEL is not a product of the fractional distillation of petroleum.

Explanation:
Petroleum is the mixture of Hydrocarbons *carbon and hydrogen containing compounds) present beneath the Earth's surface. Petroleum is formed from the remains of animals and plants beneath earth's surface in an anaerobic conditions.
Petroleum contains from small hydrocarbons (gases) to medium (liquids) and long chain hydrocarbons (Solids). These hydrocarbons are separated from each other by Fractional Distillation method (separation due to difference in boiling points)
Gasoline is a derivative of one of the fraction of petroleum used in internal combustion engines.
Jet Fuel is also derived from Kerosene and Naphtha fractions of petroleum.
While, Steel is inorganic Alloy (mixture of metals) composed of mainly Iron, Carbon and other elements.

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Answer:

Explanation:

In addition to displacing halide ions, the acetylide ion also adds to carbonyl groups. 2-Methyl-3-butyn-2-ol (MBI) is an acetylenic alcohol used in the manufacture of products for the agrochemical and specialty chemical industry. It can be synthesized by the addition of acetylene to acetone to form the alkoxide ion and, as a second step, protonation of the alkoxide ion to produce the alcohol. Complete the mechanism for 2-methyl-3-butyn-2-ol production by drawing in the products of each step and the missing curved arrows. Sodium amide deprotonates the terminal alkyne to form sodium ethynide. Draw all missing reactants and/or products in the appropriate boxes by placing atoms on the canvas and connecting them with bonds. Add charges where needed. Electron flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be create

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Answer:

Explanation:

check below for explanation.

What are the components of DNA? A. ribose sugar, cytosine, guanine, adenine, thymine, and phosphate group

B. ribose sugar, cytosine, guanine, adenine, uracil, and phosphate group

C. deoxyribose sugar, cytosine, guanine, adenine, thymine, and phosphate group

D. deoxyribose sugar, cytosine, guanine, adenine, uracil, and phosphate group

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Answer:

Explanation:

A-T G-C

What is the mass in grams of H₂ that can be formed from 54.6 grams of NH₃ in the following reaction?2 NH₃(g) → 3 H₂(g) + N₂(g)

Answers

9.6 grams of H₂ can be formed from 54.6 grams of NH₃ in the following reaction: 2NH₃(g) → 3H₂(g) + N₂(g).

According to this question, the following balanced equation is given: 2NH₃(g) → 3H₂(g) + N₂(g).

First, we convert the mass of ammonia (NH3) to moles as follows:

moles of NH3 = 54.6g ÷ 17g/mol

moles of NH3 = 3.2mol.

If 2 moles of NH3 produces 3 moles of H2.
3.2 moles of NH3 will produce 4.8 moles of H2.

Next, we convert 4.8moles of H2 to mass as follows:

mass of H2 = 4.8 × 2

mass of H2 = 9.6g of H2.

Therefore, 9.6 grams of H₂ can be formed from 54.6 grams of NH₃ in the following reaction: 2NH₃(g) → 3H₂(g) + N₂(g).

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Answer : The mass of $H_2$ is, 9.64 grams.

Explanation : Given,

Mass of $NH_3$ = 54.6 g

Molar mass of $NH_3$ = 17 g/mol

Molar mass of $H_2$ = 2 g/mol

First we have to calculate the moles of $NH_3$ .

$\text{Moles of }NH_3=\frac{\text{Given mass }NH_3}{\text{Molar mass }NH_3}$

$\text{Moles of }NH_3=(54.6g)/(17g/mol)=3.21mol$

Now we have to calculate the moles of $H_2$

The balanced chemical equation is:

$2NH_3(g)\rightarrow 3H_2(g)+N_2(g)$

From the balanced reaction we conclude that

As, 2 mole of $NH_3$ react to give 3 moles of $H_2$

So, 3.21 mole of $NH_3$ react to give $(3)/(2)* 3.21=4.82$ mole of $H_2$

Now we have to calculate the mass of $H_2$

$\text{ Mass of }H_2=\text{ Moles of }H_2* \text{ Molar mass of }H_2$

$\text{ Mass of }H_2=(4.82moles)* (2g/mole)=9.64g$

Therefore, the mass of $H_2$ is, 9.64 grams.

For the following reaction at equilibrium, which gives a change that will shift the position of equilibrium to favor formation of more products? 2NOBr(g) 2NO(g) + Br 2(g), ΔHº rxn = 30 kJ/mol

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Answer:

Based on the given reaction, it is evident that the reaction is endothermic as indicated by a positive sign of enthalpy of reaction. Thus, it can be stated that the favoring of the forward reaction will take place by upsurging the temperature of the reaction mixture.

Apart from this, based on Le Chatelier’s principle, any modification in the quantity of any species is performed at equilibrium and the reaction will move in such an orientation so that the effect of the change gets minimized. Therefore, a slight enhancement in the concentration of the reactant will accelerate the reaction in the forward direction and hence more formation of the product takes place.

A particular refrigerant cools by evaporating liquefied CCl 2F 2. How many kg of the liquid must be evaporated to freeze a tray of water to ice (at zero degrees C)? The tray contains 525 grams water. Molar heat of fusion of ice = 6.01 kJ/mol. Molar heat of vaporization of CCl 2F 2 = 17.4 kJ/mole