Select the complexes that exhibit geometric isomerism. check all that apply. check all that apply. [co(h2o)2(ox)2]− [co(h2o)2(nh3)2(ox)]+ [co(en)3]3+ [ni(co)2cl2] [ni(nh3)2(en)2]2+

Answers

Answer 1
Answer: Geometric isomerism in another name is called cis-trans isomerism or it is called E-Z isomerism.
[Co(H2O)2(ox)2]- it is an octahedral complex which has two of bidentate ligand and another two of ligand. It exists as cis-trans isomers.
[Co(en)3]³+ it is an octahedral complex which has three bidentate ligands and it cannot exist as cis-trans isomers.
[Ni(CO)2CL2] is a square planar complex which has two of one ligand another two of ligand. It exists as cis-trans isomers.
[Co(H2O)2 (NH3)2(ox)]+ it is an octahedral complex with one of bidentate ligand two of each another ligand. It exists as cis-trans isomers.
[Ni(NH3)2 (en)2]²+ is an octahedral complex with one of a bidentate ligand and two each of another ligand. It exists as cis-trans isomers.
Following compounds exhibit geometric isomerism.
[Co(H2O)2 (ox)2]-
[Co(H2O2) (NH3)2 (ox)]+
[Ni(Co)2 CL2]
[Ni(NH3)2 (en)2]²+

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Please ignore my answers because they are wrong.

Answers

Answer:

The wavelength of the radio wave is 3.003 m.

The energy of the radio wave is 6.6194* 10^(-26) J.

Explanation:

Frequency of the radio waves, ν = 99.9 MHz = 99.9* 10^6 Hz

Wavelength and frequency are related to each other by realtion:

\lambda =(c)/(\nu )

\lambda = Wavelength of the wave

c = speed of the light

ν = Frequency of the wave

\lambda =(3* 10^8 m/s)/(99.9* 10^6 s^(-1))=3.003 m

The wavelength of the radio wave is 3.003 m.

The energy of the electromagnetic wave is given by Planck's equation:

E=h* \nu

h = Planck's constant = 6.626* 10^(-34) Js

The energy of the radio wave with 99.9 MHz frequency will be:

E=6.626* 10^(-34) Js* 99.9* 10^6 s^(-1)

E = 6.6194* 10^(-26) J

The energy of the radio wave is 6.6194* 10^(-26) J.

1. Potassium (K) has an atomic mass of 39.0983 amu and only two naturally-occurring isotopes. The K-41 isotope (40.9618 amu) has a natural abundance of 6.7302%. What is the mass (in amu) of the other isotope

Answers

Answer:

38.96383282 amu

Explanation:

39.0983 = (40.9618 * 0.067302) + ( ? * (1-0.067302)

39.0983 = 2.756811064 + ( ? * 0.932698)

subtract 2.756811064 from both sides

36.34148894 = ( ? * 0.932698)

divide both sides by 0.932698

? = 38.96383282 amu

Answer:

38.96383282 amu

Explanation:

39.0983 = (40.9618  0.067302) + ( ?  (1-0.067302)

39.0983 = 2.756811064 + ( ?  0.932698)

subtract 2.756811064 from both sides

36.34148894 = ( ?  0.932698)

divide both sides by 0.932698

? = 38.96383282 amu

Please help....thank you

Answers

Answer:

a. volcanic changes create new land

Which step would help a student find the molecular formula of a compound from the empirical formula? Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound. Subtract the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound from the subscripts of the empirical formula. Divide the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound. Add the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound to the subscripts of the empirical formula..

Answers

Answer:

Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound.

Explanation:

got it right on edge 2020 :)

Answer:

Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound.

Explanation:

Devise a detailed experimental procedure to purify ~ 20 grams of benzoic acid that is contaminated with sodium chloride. Justification of the steps (including solubility calculations) that are included in the procedure. In other words, explain why the steps are being included.

Answers

Answer:

Based on the difference in solubility one can perform the process of purification of the benzoic acid contaminated with sodium chloride. The benzoic acid does not get soluble in cold water, while the sodium chloride is soluble in cold water.  

Thus, for separation, the supplementation of cold water can be done into the mixture in the experiment of purifying benzoic acid from sodium chloride. In the process, the mixture is placed on the ice bath and is stirred well, in the end, the solution is filtered. The filtrate contains sodium chloride and on the filter paper pure benzoic acid is collected.  

The voltage generated by the zinc concentration cell described by, zn(s)|zn2 (aq, 0.100 m)||zn2 (aq, ? m)|zn(s),is 16.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode.

Answers

The concentration cell is:
Zn(s) \ Zn²⁺(aq,0.100 M) // Zn²⁺(aq, x M) \ Zn(s)
voltage = 16 mV x (1V / 10³ mV) = 16 x 10⁻³ V
- In the cell notation, the concentration on the left is that of the anode and that on the right is that of the cathode.
- Oxidation takes place at the anode and reduction takes place at the cathode.
so [Zn²⁺]oxidation = 0.100 M
[Zn²⁺] reduction = x M
From Nernst equation:
Ecell = -0.0592 / n log [Zn²⁺] oxidation / [Zn²⁺]reduction
Number of electrons, n = 2. Substitute and solve for x:
16 x 10⁻³ V = - 0.0592 / 2 log (0.100 /x)
log 0.100 / x = - 0.54
0.100 / x = 0.288
x = 0.347
So the concentration of Zn²⁺ at the cathode = 0.406