If a gas has a gage pressure of 156 kPa, it is absolute pressure is approximately

Answers

Answer 1
Answer: In the given question, one important information for getting to the actual solution is not given and that is the atmospheric pressure. To find the approximate absolute pressure, it is needed to add the value of atmospheric pressure with the gage pressure.
Atmospheric pressure = 100 kPa
Then
Absolute pressure = 156 + 100 kPa
                             = 256 KPa.

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If an object has an overall negative charge, what force will it feel when itgets close to an object with an overall positive charge? *

Answers

Answer:

When a negatively charged object is brought near a positively charged object, an attractive force is produced. ... When a negatively charged object is brought near the knob of a neutral electroscope, the negative charge repels the electrons in the knob, and those electrons move down the stem into the leaves.

Answer:

Suppose that you rubbed a balloon with a sample of animal fur such as a wool sweater or even your own hair. The balloon would likely become charged and its charge would exert a strange influence upon other objects in its vicinity. If some small bits of paper were placed upon a table and the balloon were brought near and held above the paper bits, then the presence of the charged balloon might create a sufficient attraction for the paper bits to raise them off the table. This influence - known as an electric force - occurs even when the charged balloon is held some distance away from the paper bits. The electric force is a non-contact force. Any charged object can exert this force upon other objects - both charged and uncharged objects. One goal of this unit of The Physics Classroom is to understand the nature of the electric force. In this part of Lesson 1, two simple and fundamental statements will be made and explained about the nature of the electric force.

Perhaps you have heard it said so many times that it sounds like a cliché.

Opposites attract. And likes repel.

These two fundamental principles of charge interactions will be used throughout the unit to explain the vast array of static electricity phenomena. As mentioned in the previous section of Lesson 1, there are two types of electrically charged objects - those that contain more protons than electrons and are said to be positively charged and those that contain less protons than electrons and are said to be negatively charged. These two types of electrical charges - positive and negative - are said to be opposite types of charge. And consistent with our fundamental principle of charge interaction, a positively charged object will attract a negatively charged object. Oppositely charged objects will exert an attractive influence upon each other. In contrast to the attractive force between two objects with opposite charges, two objects that are of like charge will repel each other. That is, a positively charged object will exert a repulsive force upon a second positively charged object. This repulsive force will push the two objects apart. Similarly, a negatively charged object will exert a repulsive force upon a second negatively charged object. Objects with like charge repel each other.

Explanation:

Suppose you hit a 0.058-kg tennis ball so that the ball then moves with an acceleration of 10 m/s2. if you were to hit a basketball of mass 0.58 kg with the same force, what would the acceleration a of the basketball be? *graph is 4/x if that helps.

Answers

In this problem, the working equation to be used is the Newton's 2nd law of motion: Force = mass x acceleration. 


First situation: mass = 0.058 kg; acceleration = 10 m/s2

Hence, force is 0.058 kg x 10 m/s2, which is 0.58 N. Since same force is to be used, this same value is used for the second situation.

Second situation: mass = 0.58 kg; Force = 0.58 N

Since F = ma, by transposing, the acceleration could be solved by the equation, a = F/m. Thus, 0.58N/0.58 kg, the acceleration is 1 m/s2.



the pressure of a sample of gas was 97.8 kPa and the volume of the gas was 3.75 l. if the gas occupied a container with a volume of 8.00 L, what would the pressure in the container be?

Answers

If the temperature stays the same then:
P1V1=P2V2 
so:
97.8*3.75=8P
366.75=8P
P= 45.84 kPa is the new pressure

in a given year, about what percentage of all hospital patients in the US contract an infection while at the hospital

Answers

17 percent  of all hospital patients in the US contract an infection while at the hospital

at a pressure 44 kpa the gas in a cylinder has a volume of 29 liters assuming temperature remains the same,if the volume of the gas is decreased to 4liters what is the new pressure?kpa

Answers

Assuming the gas is ideal, the ideal gas law can be used. To make things simpler, Boyle's law can also be used because it denotes the inverse relationship between pressure and volume at constant temperature. The solution to be used is as follows

P1V1 = P2V2
(44)(29) = P2(4)
P2 = 319 KPa

List five factors that may affect the rate of a chemical reaction

Answers

1) temperature 
2) pressure
3) concentration
4) surface area
5) the presence of  a catalyst