Hi there!
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I believe your answer is:
m = (7/4)
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Here’s why:
⸻⸻⸻⸻
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The line passes through the points (3,4) and (-1, -3).
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Hope this helps you. I apologize if it’s incorrect.
Answer: Then the two possible values of x are 53 and -14
Step-by-step explanation:
When we have a set of numbers
{a, b, c, d, e}
The range will be equal to the difference between the larger number and the smaller number.
In our case, the set is:
{26, 33, 46, x, 9, 7, 10, 11}
First, we need to see than largest and smallest numbers in the set (ignoring x)
The largest is 46
the smallest is 7.
Now, if we considerate that x is the smallest number in the set, we will have that:
46 - x = 60
x = 46 - 60 = -14
If x is the largest number on the set, we have that:
x - 7 = 60
x = 60 - 7 = 53
Then the two possible values of x are 53 and -14
a
b
2.1
1.4
Answer:a 2.1 similar to 1.4 is 5.6 n answer to your question
Step-by-step explanation:
Answer:
1.5
Step-by-step explanation:
Answer:
uhh hope this helps
Step-by-step explanation:
A Diginacci sequence is created as follows.
• The first two terms are any positive whole numbers.
• Each of the remaining terms is the sum of the digits of the previous
two terms.
For example, starting with 5 and 8 the Diginacci sequence is
5, 8, 13, 12, 7, 10,. . .
The calculations for this example are
5 + 8 = 13, 8 + 1 + 3 = 12, 1+ 3 +1+ 2 = 7, 1 + 2 + 7 = 10.
a) List the first 26 terms of the Diginacci sequence above.
b) Find, with explanation, two starting terms for a Diginacci sequence
so that its 2021st term is 11.
c) Find, with explanation, a Diginacci sequence that has no term equal
to 11.
d) Find, with explanation, a sequence with two different starting terms
which contains five consecutive terms that are even and not all identical
Both 2 and 3 is correct.
Answer:
See explanation below
Step-by-step explanation:
Here a coin was tossed three times.
Let H = head & T = tail
Find the following:
a) The sample space:
Since a coin is tossed thrice, all possible outcome would be:
S = { HHH, HHT, HTH, HTT, TTT, TTH, THH, THT}
b) i) A = Exactly 2 tails: Here exactly 2 tails were recorded.
A = {HTT, TTH, THT}
ii) B = at least two tails: Here 2 or more tails were recorded.
B = {HTT, TTT, TTH, THT}
iii) C = the last two tosses are heads:
C = { HHH, THH}
c) List the elements of the following events:
i) A. This means all outcomes in A
= {HTT, TTH, THT}
ii) A∪B. A union B, means all possible outcomes present in A or B or in both
= {HTT, TTH, THT, TTT}
iii) A∩B. This means all possible outcomes of A that are present in B.
= {HTT, TTH, THT}
iv) A∩C. All outcomes A that are present in B
= {∅}
The sample space of tossing a coin three times consists of eight possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT. Events A, B, and C can be determined by listing the appropriate outcomes. The intersection and union of events A and B can also be determined.
(a) The sample space, Ω, of tossing a coin three times can be determined by listing all the possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT.
(b) i. A = {HHT, HTH, THH}
ii. B = {TTT, TTH, THT, HTT, HHT, HTH, THH}
iii. C = {HTH, TTH}
(c) i. A = {HHT, HTH, THH}
ii. A∪B = {HHT, HTH, THH, TTT, TTH, THT, HTT, HHT}
iii. A∩B = {HHT, HTH, THH}
iv. A∩C = {HHT, HTH}
#SPJ3
Answer:
Step-by-step explanation:
Hello, first of all we can divide by 2.
The discriminant is negative so there is no real solutions.
Thank you.