What is the solution to the story?
13.80
10.60
07.00
8.25
Answer:
C. $7.00
Step-by-step explanation:
8 times 7 is 56 + 5 = 61
B 30 26 27 37 24
Assume the paired data came from a population that is normally distributed.
Answer:
9.0
Step-by-step explanation:
Mean = Sum of terms/Number of terms
For Data Set A
Mean = 32 + 30 + 49 + 45 + 33/5
= 189/5
= 37.8
For Data Set B
Mean = 30 + 26 + 27 + 37 + 24/5
= 144/5
= 28.8
Hence, the Mean difference is calculated as the absolute difference between the Mean of Data set A and Data set B
Mean Difference = 37.8 - 28.8
= 9.0
Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so .
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when .
So
A task time of 177.125s qualify individuals for such training.