The magnitude of each charge is 3.94 x coulombs.
We have a pair of equal charges are separated by 0.75 m and there's a 2500 N force acting on them.
We have to strength of the charge.
According to Coulomb's law, the formula to calculate the force between the two point charges (say q and Q) separated by a some distance (say r) is given by -
F =
According to the question -
Force between two point charges equals to = F = 2500 N
Distance between the point charges = 0.75 m
Let's assume the magnitude of each charge be x, therefore using the coulomb's law, we get -
F =
coulombs
Hence, the magnitude of each charge is 3.94 x coulombs.
To understand more about coulomb's law visit the link below -
#SPJ2
Answer:
4.5643546 × 10^ -4
Explanation:
The distance between the roof and the ground where the balloon water was dropped is 30.65 meters. This is computed using the free fall formula which state that the height or distance is equal to the time it takes object to hit the ground times the constant gravity. In this case, 2.5 seconds times 9.807 meter per square second will then give us the 30.65 meter.
you could use SUVAT to work out the deceleration and then use F=ma
S= 79m U=28m/s V=0m/s A=? T=n/a
V^2 = U^2 + 2AS so 0 = 28^2 + 158A so -158A = 784
A= 4.962 (3dp)
so F = ma = 4.962 *1330 = 6599.494N (3dp)