Explanation:
Below is an attachment containing the solution.
V = Voltage in the circuit = 24 Volts
i = Current flowing in the circuit = 2 A
P = Total power dissipated in the circuit.
Total Power dissipated in a current carrying circuit is given as
P = i V
inserting the above values of the current and voltage in the above equation , we get
P = (2 A) (24 V)
P = (2 x 24) (AV)
P = 48 Watt (Since Ampere -Volt = watt)
Answer:When a sphere rolls down an inclined plane without slipping, its linear acceleration at the bottom can be calculated using the following formula:
a = g * sin(theta)
where "a" is the linear acceleration, "g" is the acceleration due to gravity (approximately 9.8 m/s^2), and "theta" is the angle of inclination of the plane.
Let's break down the formula step by step:
1. First, we need to determine the component of the gravitational force that acts parallel to the inclined plane. This component is given by g * sin(theta), where "g" is the acceleration due to gravity and "theta" is the angle of inclination.
2. Since the sphere is rolling without slipping, the frictional force between the sphere and the inclined plane is responsible for its linear acceleration. This frictional force is equal to the component of the gravitational force parallel to the plane.
3. Therefore, the linear acceleration of the sphere as it reaches the bottom of the inclined plane is equal to the component of the gravitational force parallel to the plane, which is g * sin(theta).
For example, if the angle of inclination, theta, is 30 degrees, the linear acceleration of the sphere at the bottom of the inclined plane would be:
a = g * sin(30) = 9.8 m/s^2 * 0.5 = 4.9 m/s^2
So, the linear acceleration of the sphere as it reaches the bottom of the inclined plane would be 4.9 m/s^2 when the angle of inclination is 30 degrees.
Explanation: