If a plane can travel 450 miles per hour with the wind and 410 miles per hour against the wind, find the speed of the plane without a wind and speed of the wind. I need help with this one :(

Answers

Answer 1
Answer:

The speed of the plane without a wind is 430 miles/hr and speed of the wind is 20 miles/hr.

What is Speed ?

Speed is a rate of change of distance with respect to time. i.e. v=dx÷dt. Speed can also be defined as distance over time

i.e. speed= distance ÷ time

it is denoted by v and its SI unit is m/s. it is a scalar quantity.

Speed shows how much distance can be traveled in unit time.

To find dimension for speed is, from formula

Speed = Distance ÷ Time

Dimension for distance is [L¹] ,

Dimension for Time is [T¹],

Dividing dimension of distance by dimension of time gives,

{L¹] ÷ [T¹] = [L¹T⁻¹]

Dimension for speed is [L¹T⁻¹].

Consider,

Speed of the plane = v

Speed of the wind = u

Speed of the wind in the direction of wind is,

v + u = 450 miles/hr.....1

Speed of the wind in the opposite direction of wind is,

v - u = 410 miles/hr.....2

Adding equation 1 and 2

2v = 860

v = 430 miles/hr

Subtracting equation 1 and 2

2u = 40

u = 20 miles/hr

Hence the speed of the plane without a wind is 430 miles/hr and speed of the wind is 20 miles/hr.

To know more about Speed :

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Answer 2
Answer:


the plane is 430 and the wind it 20miles



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Answers

Most asteroids lie between the orbits of Mars and Jupiter. This certain area is called the asteroid belt. This so-called asteroid belt is inhabited by numerous asteroid, where a lot of collisions do occur. The asteroid belt was formed from the collisions of planetesimals.

Answer:

b. Mars and Jupiter.

Explanation:

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two objects were lifted by machine one object had a massive 2 kg it was lifted at a speed of 2 m/s the other had a massive 4 kg and was lifted at a rate of three meters per second which object has more kinetic energy

Answers

Kinetic energy =(1/2) (mass) (speed²)

First object:  KE = (1/2) (2 kg) (2m/s)² =  4 joules during the lift.

Second object:  KE = (1/2) (4kg) (3 m/s)² = 18 joules during the lift.

The second object has more kinetic energy while it's being lifted
than the first object has while it's being lifted. Once they reach their
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What is the energy of work done lifting 2kg mass rocket to a height of 130 m

Answers

Work done to lift the mass is given by

W = mgH

here we know that

m = mass = 2 kg

g = acceleration due to gravity = 9.8

H = height = 130 m

now using the above equation we can write

U  = 2* 9.8 * 130

U = 2548 J

so the energy required to do the work is 2548 J


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Explain Newton's third law in your own words.

Answers

Newton's third law states "for every action, there is an equal and opposite reaction."

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Answers

At certain altitude, the temperature of air decrease, The air becomes saturated and water vapour molecules starts condensing.

As the altitude of air increase, the atmospheric pressure decrease due to which the temperature of the air decrease. The water molecules in the atmosphere start condensing, which saturate the air (that is air can no hold water molecules), due to which the water vapour molecules starts condensing and falls on the earth in the form of rain.

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B:The surface of the coating is rough, so light that shines on it gets scattered in many directions.

C:The coating bends light that passes through it and prevents the light from reaching the user’s eyes

D:The surface of the coating allows light from the room to pass through but blocks the light from the screen.

Answers

Answer:

The correct answer is D.

D:The surface of the coating allows light from the room to pass through but blocks the light from the screen.

Explanation:

Glare is produced on a computer screen when light from some external source reflects on the screen.

Anti-glare coating do not absorb light to reduce glare but they actually reduce glare by encouraging the light from the room to pass through the screen so that less light is reflected. Polarized lenses absorbs light to reduce glare, not anti-glare coating.

Answer: d

Explanation: