B.(7.5, –3.5) and (7.5, 3.5)
C.(7.5, 1.2) and (7.5, 2.3)
D.(7.5, –3.5) and (7.5, 7)
The points between whom the distance is 3.5 units apart are (7.5, 1.2) and (7.5, -2.3).
Given is to find the points between whom the distance is 3.5 units apart.
Using the distance formula for the points (7.5, 1.2) and (7.5, -2.3), we get-
d² = (- 2.3 - 1.2)² + (7.5 - 7.5)²
d² = (3.5)²
d = 3.5 units
Therefore, the points between whom the distance is 3.5 units apart are (7.5, 1.2) and (7.5, -2.3).
To solve more questions on functions, expressions and polynomials, visit the link below -
#SPJ6
What is the value of x?
8x + 4y = 156
Answer:
[12, 15]
Step-by-step explanation:
{6x + 5y = 147
{8x + 4y = 156
-¾[8x + 4y = 156]
{6x + 5y = 147
{-6x-3y=-117← New Equation
________________
2y = 30
______
22
y = 15 [Plug this back into both equations to get the x-coordinate of 12]; 12 = x
So, using the Elimination Method, what I did here was took the bottom equation and multiplied it by -¾, turning 8x to -6x, canceling out all x-terms.It does not matter which variable you choose to eliminate, as long as you know what you are doing.
I am joyous to assist you anytime.