(2^8 *3^-5* 6^0)^-2 * ((3^-2)/(2^3))^4 * 2^28
anything to the 0 power is 1
(2^8 *3^-5* 1)^-2 * ((3^-2)/(2^3))^4 * 2^28
using the power of power property to take the power inside
(2^(8*-2) *3^(-5* -2) * (3^-2*4)/(2^3*4) * 2^28
simplify
2^ -16 * 3^10 * 3^-8 /2*12 * 2^28
get rid of the division by making the exponent negative
2^-16 * 3^10 * 3^-8 *2*-12 * 2^28
combine exponents with like bases
2^(-16-12+28) * 3^(10-8)
2^(0) *3^2
anything to the 0 power is 1
1*9
9
Select the state that best describes this equation.
A. The equation is a nonlinear function.
B. The equation is not a function.
C. The equation is a linear function.
equation of line has form of y=kx±b, so
Answer: C
Answer:
C
Step-by-step explanation:
i'm doing a test right now on this question
y = 3x + 12
Select one:
a. 2 /19 comma 2 / 33
b. negative 2 / 19 comma negative 33 / 2
c. negative 19 / 2 comma negative 33 / 2
d. 19 / 2 comma 33 / 2
Answer:
c. negative 19 / 2 , negative 33 / 2
Step-by-step explanation:
x − y = 7
y = 3x + 12
Substitute y = 3x + 12 into x − y = 7
x − (3x + 12) = 7
x - 3x - 12 = 7
-2x - 12 = 7
-2x = 19
x = -19/2
Substitute x = -5/2 into x − y = 7
-19/2 − y = 7
y = -19/2 - 7
y = - 5/2 - 14/2
y = -33/2
Answer:
x = -19/2, y = -33/2
Answer:
B=8
Step-by-step explanation:
15² + b² = 17²
225 + b² = 289 (Subtract 289 - 225)
b² = 64 (Find the square root of 64)
√64 = 8
Answer:
This is true.
Congruent triangles have the same shape and the same size. So, you can position them so that one is superimposed (line up perfectly) on the other.
Answer:
True
Step-by-step explanation: