when the pressure that a gas exerts on a sealed container changes from 3.74 atm to ____ atm, the temperature changes from 394 K to 789 K

Answers

Answer 1
Answer: Gay-Lussacs law gives the relationship between pressure and temperature of a gas.
It states that pressure of gas is directly proportional to the temperature at constant volume.
P/T = k
Where k - constant
P1/T1 = P2/T2
Where parameters for the first instance are on the left side and parameters for the second instance on the right side of the equation.
3.74 atm /394 K = P/789 K
P = 7.49 atm
Answer 2
Answer:

Answer:

7.49 atm

Explanation:


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1) How many kJ are absorbed when 45.2 g of water at 31.3 oC is heated to 76.9 oC? 2) Calculate the total heat released in kcal when 72.1 g water at 25.2 oC is cooled to 0 oC and freezes. 3) How many kilojoules are required to heat 55,500 mg of gold with specific heat = 0.129 J/g oC is heated from 24.6 oC to 123.4 oC? 4) Calculate the heat needed in kcal to change 45.6 g of water at 100 oC to change into steam.

Answers

Answer:

1. Q = 8.66 KJ

2. Q = 7.58 Kcal

3. Q = 0.71 KJ

4. Q = 24.31 Kcal

Explanation:

1. The quantity of heat absorbed can be determined by:

       Q = mcΔθ

where: Q is the quantity of heat absorbed or released, m is the mass of the substance, c is the specific heat capacity of water = 4.2 j/g^(0)C and Δθ is the change in temperature.

           = 45.2 × 4.2  × (76.9 - 31.3)

           = 8656.704

∴       Q = 8.66 KJ

The quantity of heat absorbed is 8.66 KJ.

2. Q = mcΔθ + mL

Where L is the latent heat of fusion of ice = 334 J.

       = m(cΔθ + L)

       = 72.1(4.2 × 25.2 + 334)

   Q = 31712.464 J

       = 7579.466 calories

The total heat released is 7.58 Kcal.

3. Q = mcΔθ

      = 55.5 × 0.129 × (123.4 - 24.6)

     = 707.3586

The quantity of heat required to increase the temperature of gold is 0.71 KJ.

4. Q = mL

Where: L is the specific latent heat of vaporization = 533 calories.

     Q  = 45.6 × 533

      = 24304.8

The quantity of heat required to change water to steam is 24.31 Kcal.

The molecule XeF2 does not obey the octet rule. Draw its Lewis structure and state the type of octet-rule exception. Include lone pair electrons in the Lewis structure.

Answers

Answer: See attachment.

Explanation:

Exceptions to the octet rule fall into three categories:

  • An incomplete  octet.
  • An odd number of electrons.
  • More than eight valence electrons around the  central atom.  

In addition to the 3s and 3p orbitals, xenon also has 3d orbitals that can be used in bonding. These orbitals enable xenon to form an expanded octet.

Whats the difference between china and Europe

Answers

Answer:

the difference is they arnt close

Explanation:

Answer:

China is communist, Europe isn't.

Explanation:

What is the mass of a neutron close to

Answers

Answer:

The free neutron has a mass of 939,565,413.3 eV/c2, or 1.674927471×10−27 kg, or 1.00866491588 u. The neutron has a mean square radius of about 0.8×10−15 m, or 0.8 fm, and it is a spin-½ fermion.

Mass: 1.67492749804(95)×10−27 kg; 939.56542052(54) MeV/c2; 1.00866491588...

Composition: 1 up quark, 2 down quarks

Electric charge: 0 e; (−2±8)×10−22 e (experimental limits)

Magnetic polarizability: 3.7(20)×10−4 fm3

Coloumb's Law shows that opposite charges (positive and negative) attractwhereas charges that are both positive or both negative repel and a greater
distance decreases the force between objects. TRUE or FLASE​

Answers

Explanation:

TRUE

the answer is true. Trust me. Im an expert at this.

Draw all the structural isomers for the molecular formula C3H8O. Be careful not to draw any structures by crossing one line over another; the system needs to know where you intend connections to be between atoms.

Answers

Answer:

The three isomers having the molecular formula C_(3) H_(8)O are drawn in the figure below.

Explanation: