James bought 5 boxes of cookies and 2 cakes at the store for his party. The cakes cost $4 each and his total bill was $28.50, how much was each box of cookies?
Answers
Number of cakes bought by James = 2
Cost of each cakes = $4
Total bill paid by James = $28.50
Let us assume the cost of the each boxes of cookies = x
Then
5x + (2 * 4) = 28.50
5x + 8 = 28.50
5x = 28.50 - 8
5x = 20.50
x = 20.50/5
= 4.10
So we can see from the above deduction that the cost of each boxes of cookies bought by James is $4.10
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B. 3%
C. 33%
D. 25%
Answers
Answer:
The correct option is B.
Step-by-step explanation:
It is given that the total area of a dartboard is 30,000 mm² and the area of the bull's-eye is 1000 mm².
The probability of getting a bull's-eye is
Therefore the correct option is B.
Answers
x= -b +(or minus, both) √b² + 4ac
--------------------------------------------
2a
So, your numbers would be: a = 3
b = 13
c = 10
Then, solve: x = -13 +(or minus, both) √169 + 120
--------------------------------------------------
6
= -13 +(or minus, both) 17
------------------------------------
6
So, first do the plus: -13 + 17
--------------
6
= 2/3
Then do the minus: -13-17
------------
6
= 5
Your answer is: 2/3 and 5
( These problems always have two answers)
Answers
Answer: 3.47
Step-by-step explanation:
Absolute value is distance from zero.
Answers
cost of each rides:$0.50
total no. of rides taken:11
cost of 11 rides:11×$0.50
=$5.50
total amount spent:$5.50+$6
=$11.50
^^hope it helps :) sorry if the answer is wrong
Answer: 11.50
Step-by-step explanation:
6$ to get in+ rides=$
11(rides)*.50(price of rides)=5.50
5.50+6=$11.50
Answers
Answer:
Step-by-step explanation:
You solve a question like this by finding the slope and intercept of the desired line and putting those values into the answer form.
__
The relationship between slopes of perpendicular lines is that one is the negative reciprocal of the other.
The slope-intercept form of the equation for a line is ...
y = mx + b . . . . . . where m is the slope and b is the y-intercept
The given line is in "slope-intercept form," so you can identify the slope as 4 and the y-intercept as 6. (For this question, the y-intercept of the given line is irrelevant.)
Using the relationship between slopes of perpendicular lines, you now know the slope of the line you want is m = -1/(slope of given line) = -1/4. This is the coefficient of x in the slope-intercept form, so fills the blanks on the left.
To make the line go through the point (1, 1), you need to choose a y-intercept that makes (x, y) = (1, 1) a solution to the equation. For a y-intercept of "b", that means ...
y = -1/4x + b
1 = -1/4·1 + b . . . . . . . . fill in the values of x and y at the given point
1 + 1/4 = b = 5/4 . . . . . add 1/4 to both sides of the equation
Now you know the equation you want is ...
Answers
we are given points A and B
A=(3,150)
B=(4,200)
we can find points
x1=3 , y1=150
x2=4 , y2=200
(a)
the change in y-values from Point A to Point B is
now, we can plug values
...........Answer
(b)
the change in x-values from Point A to Point B is
now, we can plug values
...........Answer
(c)
the rate of change of the linear function in feet per second is
now, we can plug values
.................Answer
The straight line graph indicates that rate of change of the distance traveled with time by the red kangaroo is a constant
- The change in y-values from point A to point B is 50 feet.
- The change in x-values from point A to point B is 1 second.
- The rate of change of the linear function is 50 feet per second.
Reasons:
The y-values at point A = 150 feet
The y-values at point B = 200 feet
Change in y-values from point A to point B, Δy is given as follows;
Δy = y-values at point B - y-values at point A
Δy = 200 feet - 150 feet = 50 feet
Change in y-values from point A to point B, Δy = 50 feet
The x-values at point A = 3 seconds
The x-values at point B = 4 seconds
Change in x-values from point A to point B, Δx is given as follows;
Δx = x-values at point B - x-values at point A
Δx = 4 seconds - 3 seconds= 1 second
Change in x-values from point A to point B, Δx = 1 second.
The rate of change of the linear function is , therefore, we have;
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