Orlando invested $16,000 in an eight-year CD bearing 6.5% interest, but needed to withdraw $3,500 after five years. If the CD’s penalty for early withdrawal was one year’s worth of interest on the amount withdrawn, when the CD reached maturity, how much less money did Orlando earn total than if he had not made his early withdrawal?a.
$227.50
b.
$682.50
c.
$910.00
d.
$455.00

Answers

Answer 1

Answer: B is the correct answer. Firstly, you have to work out the amount of interest earned per year by multiplying the sum invested ($16,000) by the interest rate (6.5%, or 0.065). Then multiply the result by eight to find out how much money Orlando would get when the CD reaches maturity if he doesn't withdraw any money. To calculate interest when money is withdrawn, multiply the annual interest by five, to work out how much interest Orlando earns in the first five years. Then work out the interest on the reduced investment ($16,000 - $3,500) in the same way and multiply by three to calculate the remaining three years' interest. Add the total interest for three years to the total interest to five years, which will tell you how much interest Orlando recieves when he makes the withdrawal. Finally, you can now take this away from the interest he would have made if he had not made a withdrawal, and this will tell you the difference.

Answer 2

Answer:

The real correct answer is C. $190.00

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A function g(x) has x-intercepts at (1/2, 0) and (6, 0). which could be g(x)?A. g(x) = 2(x + 1)(x + 6)
B. g(x) = (x – 6)(2x – 1)
C. g(x) = 2(x – 2)(x – 6)
D. g(x) = (x + 6)(x + 2)

Answers

The x-intercepts of a function are used to express the function into factored form:
From (1/2, 0)
(x - 1/2)

From (6, 0)
(x-6)

(x - 1/2) (x-6) = 0
(2x -1)(x-6) = 0

The function is:
B. g(x) = (x – 6)(2x – 1)

Answer:

I believe the answer is B.

There were 480 people at play. The admission price was $2 for adults and $1 for children. The admission receipts were $770. How many adults and how many children attended?

Answers

Answer:

290 adults and 190 children attended the Play.

Step-by-step explanation:

Given:

Total number of people in play = 480

Let the number of adults be x

and Number of children be y

Hence we can write the equation as;

$x+y=480 \ \ \ \ equation \ 1$

Also Given:

Price for 1 adult = $2

Price for 1 children = $1

Total admission receipts = $770

Hence we can write the equation as;

$2x+y =770 \ \ \ \ equation \ 2$

Now We will subtract equation 1 from equation 2 we get;

$(2x+y)- (x+y) =770-480\n2x+y-x-y= 290\nx= 290$

Now substituting the value of x in equation 1 we get;

$290+y =480\ny =480 -290\ny= 190$

Hence 290 adults and 190 children attended the Play.

Final answer:

The problem is solved by creating two equations based on the given information and solving the system of equations to find that there were 290 adults and 190 children who attended the play.

Explanation:

To solve the problem of determining how many adults and children attended the play, we need to set up a system of equations.

Let A be the number of adults and C be the number of children who attended the play. We are given two pieces of information:
The total number of people at the play was 480, which gives us the equation A + C = 480.

The total amount of money collected from admissions was $770. Since adults pay $2 and children pay $1, the equation is 2A + C = 770.

Now we have a system of two equations:
A + C = 480

2A + C = 770

To solve this system, we can subtract the first equation from the second equation to eliminate C:

2A + C - (A + C) = 770 - 480

which simplifies to:

A = 290

Now, plug A = 290 into the first equation to find C:

290 + C = 480

Subtract 290 from both sides:

C = 190

So, there were 290 adults and 190 children at the play.

Learn more about system of equations here:

brainly.com/question/21620502

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URGENTWhat is the area of trapezoid ABCD ?

Enter your answer as a decimal or whole number in the box. Do not round at any steps.

units²

Answers

Answer:

The answer to your question is Area = 62.5 u²

Step-by-step explanation:

Area = $c (a + b)/(2)$

a and b are bases

c = heigth

dAD = $\sqrt{(x2 - x1)^(2) - (y2 - y1)^(2) }$

dAD = $\sqrt{(-1 + 13)^(2) - (5 + 11)^(2) }$

dAD = $\sqrt{(12)^(2) - (16)^(2) }$

dAD = $√(144 + 256)$

dAD = $√(400)$

dAD = 20 u

dBC = $\sqrt{(3 - 0)^(2) - (2 + 2)^(2) }$

dBC = $√(9 + 16)$

dBC = $√(25)$

dBC = 5 u

dAB = $\sqrt{(3 + 1)^(2) - (2 - 5)^(2) }$

dAB = $\sqrt{(4)^(2) - (-3)^(2) }$

dAB = $√(16 + 9)$

dAB = $√(25)$

dAB = 5u

Area = $5 (20 + 5)/(2)$

Area = $5 (25)/(2)$

Area = 5(12.5)

Area = 62.5 u²

Answer:

62.5 units^2

Step-by-step explanation:

Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 2−x and y = 4x + 3 intersect are the solutions of the equation 2−x = 4x + 3. (4 points) Part B: Make tables to find the solution to 2−x = 4x + 3. Take the integer values of x only between −3 and 3. (4 points) Part C: How can you solve the equation 2−x = 4x + 3 graphically? (2 points) PLez Answer 50 points

Answers

Answer:

Step-by-step explanation:

Part A:

We have two lines: y = 2 - x and y = 4x + 3 . Given two equations that are both required to be true. The answer is the points where the lines cross, this means we have to make the equations equal to each other. It will look like this:

2 - x = 4x + 3

Part B:

In order to solve the equation we need to put the like terms together. So we will add x on each side.

2 - x = 4x + 3

+x +x

So now we get:

2 = 5x + 3

Now that x is on one side and is positive we will move 3 on the left side by subtracting it from each side.

2 = 5x + 3

-3 -3

So now we get:

-1 = 5x