MATHEMATICS HIGH SCHOOL

A cell phone company orders 600 new phones from a manufacturer. If the probability of a phone being defective is 3.5%, predict how many of the phones are likely to be defective. Round to the nearest whole number.A) 18 phones
B) 210 phones
C) 21 phones
D) 26 phones

Answers

Answer 1
Answer: To calculate percetages, move the decimal point 2 places to the left.

3.5% = 0.035

Then multiply by the decimal: 

600 • 0.035 = 21

Your answer is C: 21 phones

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How long will it take a sample of radioactive substance to decay to half of its original amount, if it decays according to function A(t)=750e^ -.119t, where t is the time in years? Round your answer to the nearest hundredth year. T equals time???? I don't see the time anywhere! Can someone please help me figure this mess out?

Answers

This is the formula to find the amt. A of that radioactive substance after time t.

A_t=750e^(0.119t)

We want to find out low long it will take for A to become half of its original amount.
We don't know the original amount, and the substance is not decaying at a constant rate (but rather an exponential one) so we can't answer that question.

Is there any information you forgot to give? Double check yourself.

The combined area of two squares is 45 square centimeters. Each side of one square is twice as long as a side of the other square. What is the length of each side of the larger square?

Answers

a - side of the square
a₁ - arm the small square
a₂ - larger side of the square
2a₁ = a₂  we put into the equation 2
(a₁)² + (a₂)² = 45cm²

2a₁ = a₂
(a₁)² + (2a₁)² = 45cm²
(a₁)² + 4(a₁)² = 45cm²
5(a₁)² = 45cm²
(a₁)² = 9cm²
a₁ = √(9cm²) = 3cm
a₂ = 2a₁ = 2*3cm = 6cm
A₁ = (a₁)² = (3cm)² = 9cm²
A₂ = (a₂)² = (6cm)² = 36cm²
A₁ + A₂ = 9cm² + 36cm² = 45cm²

The number of nails of a given length is normally distributed with a mean length of 5 in. and a standard deviation of 0.03 in. In a bag containing 120 nails, how many nails are more than 5.03 in. long?a.about 38 nails
b.about 41 nails
c.about 16 nails
d.about 19 nails

Answers

The length 5.03 inches belonged to the first range of span of standard deviation. The probability of having length below 5.03 is equal to 68%. The proprobability of having length above 5.03 therefore is (100-68)/2 or equal to 16%. 16% of 120 nails given is 19.2 or D. about 19 nails.

Answer:

(D) About 19 nails

Step-by-step explanation:

It is given that mean length= 5 inches and the standard deviation =0.03.

In order to standardize x to z, we use the formula=\frac{(x-{\mu})}{{\sigma}}.

Now, probability of nails having length more than 5.03= P(x>5.03)=P(z>((5.03-5))/(0.03))

=P(z>1)

=0.1587 b(Using the normal probability table)

In a bag of 20 nails, nails having length more than 5.03 inches=20{*}0.1587=19.004

= about 19 nails.

Can someone please help me?

Answers

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Answers

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Answers

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