The speed of the bike is calculated by dividing the total distance travelled by the total time taken, which in this case is 50 meters divided by 10 seconds. This yields a speed of 5 meters per second.
This involves a concept from Physics called speed.
Speed is defined as the distance covered by an object divided by the time taken to cover that distance.
Since the bike moves 50 meters in 10 seconds, to calculate the speed:
Identify the distance covered which is 50 meters.
Identify the time taken which is 10 seconds.
Divide the distance by the time to get the speed = 50 m / 10 s = 5 m/s. So, the speed of the bike is 5 meters per second.
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Answer:
We know that
Speed = Distance/ Time
Explanation:
Speed = 50/10
= 5 m/s
Answer:
the 25 kg one
Explanation:
The higher the weight the higher the inertia.
lets suppose we blow wind at both of these objects at a very high rate equally, u will notice after some time depending on the strength of wind the 8kg object will probably move earlier than the 25 kg one.
Period is defined as the time required to complete one cycle which is also related to frequency. Period is presented by an equation P = 1/f where p is the period, and f is the frequency. The unit is in second. Frequency is defined as the number of circular revolutions in a given time interval and it is in Hertz (Hz) = 1s^-1. Velocity s defined as the arc traveled at a given time with the equation v=l/t where v is the velocity, l is the length and t is time. The unit is in m/s.
The average time to travel just between 0.25m and 0.50m is_____
Given the time taken to travel the second 0.25m section, the velocity would be____m/s
1. Average time for the first 0.25 m: 2.23 s
Explanation:
The average time that it takes for the car to travel the first 0.25 m is given by the average of the first three measures, so:
2. Average time to travel between 0.25 m and 0.50 m: 0.90 s
Explanation:
First of all, we need to calculate the time the car takes to travel between 0.25 m and 0.50 m for each trial:
t1 = 3.16 s - 2.24 s = 0.92 s
t2 = 3.08 s - 2.21 s = 0.87 s
t3 = 3.15 s - 2.23 s = 0.92 s
So, the average time is
3. Velocity in the second 0.25 m section: 0.28 m/s
Explanation:
The average velocity in the second 0.25 m section is equal to the ratio between the distance covered (0.25 m) and the average time taken (0.90 s):
Answer:
1. 2.23
2. 0.90
3. 0.28
Answer: 8 m
Explanation:
From the equation distance = velocity * time, we can find the distance from a velocity vs. time graph by finding the area under the curve, since we get that area from multiplying velocity and time together.
For the first 0.5 seconds, the velocity is 16 m/s and the change in time is 0.5.
16 * 0.5 = 8 m.
Learn more about the relationship between distance and velocity here: brainly.com/question/29409777