In a laboratory experiment, an ultrasound detector located at D is used to measure the distances of two moving objects, P and Q. At a certain moment, P and Q are located as shown in the diagram. What is distance PQ?. a) 6.82. b)5.66. c)4.74. d)4.24. e)3.89. .

Answers

Answer 1

Answer: Triangle PDQ has:

Side "p" is opposite Angle P

Side "d" is opposite Angle D = 45º + 23º = 68º

Side "q" is opposite Angle Q

Use the Law of Cosines:

d² = p² + q² − 2 • p • q • cos(D)

d² = (4.24)² + (4.24)² − 2 • (4.24) • (4.24) • cos(68º)

d² = 2(4.24)² − 2(4.24)² • cos(68º)

d² = 2(4.24)² • [ 1 – cos(68º) ]

d = 4.74 ft

Answer 2

Answer:

The distance PQ is 4.74 feet.

Calculations and Parameters:

Triangle PDQ has:

Side "p" is opposite Angle P
Side "d" is opposite Angle D = 45º + 23º = 68º
Side "q" is opposite Angle Q

If we use the Law of Cosines:

d² = p² + q² − 2 • p • q • cos(D)

d² = 2(4.24)² • [ 1 – cos(68º) ]

d = 4.74 ft

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Answers

I am going to assume 2.1 metres per second and that we're rounding acceleration due to gravity to -10 metres per second squared. At the highest point, velocity is going to be 0. v= intial velocity + acceleration*time, sub in 0 for velocity, 2.1 for initial velocity and -10 for acceleration to get 0= 2.1-10t. Now solve for t. t=0.21 seconds.

Answer:

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Explanation:

Apex; good luck all! :)

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Answers

It depends on the tempature of something or an object,
The Object has to go from hot to cold, that is a primary example of how heat transfer occurs

Which states the law of conservation of energy?A.
Energy cannot be created or destroyed, but it can be converted or changed into different forms.

B.
Energy can be created or destroyed, and it can be converted or changed into different forms.

C.
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D.
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Answers

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