What is the total mass of oxygen in 1.00 mole of Al2(CrO4)3

Answers

Answer 1
Answer: 1 mol of this atom would yield 12 moles of Oxygen, (using the number of atoms that they gave in 1 molecule of Al2(CrO4)3. Therefore, the atomic mass of Oxygen is 16, and there are 12 moles of Oxygen atoms. In total, the mass would be 12  * 16 = 192 grams of Oxygen.
Answer 2
Answer:

Final answer:

The compound Al2(CrO4)3 contains 12 oxygen atoms per formula unit. Knowing that one mole of oxygen atoms has a mass of 16.00 grams, the total mass of oxygen in 1.00 mole of Al2(CrO4)3 is 12 * 16.00 = 192.00grams.

Explanation:

The primary task here is to find the total mass of oxygen in 1.00 mole of Al2(CrO4)3. This is a classic chemistry problem that involves understanding the composition and molar mass of compounds. In the compound Al2(CrO4)3, the subscript 3 after (CrO4) means there are three chrome tetraoxides in one formula unit of the compound.

Every CrO4 ion is composed of one chromium atom and four oxygen atoms. Therefore, three CrO4 ions will contain 3 * 4 = 12 oxygen atoms.

Knowing that one mole of oxygen atoms weighs approximately 16.00 grams, we can find the total mass of oxygen in the compound by multiplying this molar mass by the number of oxygen atoms. Again, in one mole of Al2(CrO4)3 we have 12 oxygen atoms, hence 12 * 16.00 g = 192.00 grams.

So, the total mass of oxygen present in 1.00 mole of Al2(CrO4)3 is 192.00 grams.

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Answers

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- - - - -

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Answers

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Answers

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Answers

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Answers

Explanation:

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