Answer:
0.6 gallons of pure saline
Step-by-step explanation:
15-12=3
3=×0.03
20 gallons ×0.03=0.6 gallons
Answer:
55 m/s
Step-by-step explanation:
average velocity
the solutions are for: a. 118 with a remainder of 10, b. 169 with a remainder of 10.
What about others and what is remainder?
a. 2014 ÷ 17 = 118 with a remainder of 10
Check: 118 x 17 + 10 = 2014
b. 3716 / 22 = 169 with a remainder of 10
Check: 169 x 22 + 10 = 3716
c. 4 691 ÷ 13 = 361 with a remainder of 8
Check: 361 x 13 + 8 = 4691
d. 1 168 ÷ 16 = 73
Check: 73 x 16 = 1168
e. 9 603 / 27 = 355 with a remainder of 18
Check: 355 x 27 + 18 = 9603
f. 7 834 ÷ 19 = 411 with a remainder of 5
Check: 411 x 19 + 5 = 7834
g. 5 186 ÷ 21 = 247 with a remainder of 19
Check: 247 x 21 + 19 = 5186
h. 6 437 / 14 = 459 with a remainder of 1
Check: 459 x 14 + 1 = 6437
Therefore, the answers are:
a. 118 with a remainder of 10
b. 169 with a remainder of 10
c. 361 with a remainder of 8
d. 73
e. 355 with a remainder of 18
f. 411 with a remainder of 5
g. 247 with a remainder of 19
h. 459 with a remainder of 1
In arithmetic, the remainder is the amount left over after performing a division operation when one number is divided by another.
For example, when you divide 17 into 2014, you get 118 with a remainder of 10. This means that 17 goes into 2014 exactly 118 times, with 10 left over. The remainder is always less than the divisor and indicates how much is left after dividing the dividend as equally as possible by the divisor.
To know more about Arithmetic related questions visit:
#SPJ1
The question can be addressed using the principles of Normal Distribution. Given the z-chart, 8 ounces is the observed value for the 99.5th percentile, which equates to approximately 2.58 standard deviations. Therefore, the mean setting of the coffee machine should be set around 8 ounces for the cup to overflow only 0.5% of the time.
The situation described in the question is a typical case of application of Normal Distribution. As a reminder, in a Normal Distribution, 99.7% of the values lie within 3 standard deviations of the mean. The question states that the cup should overflow only 0.5% of the time. Therefore, we need to consider the 99.5% of the left side under the normal curve (as we're considering the upper limit), which corresponds to around 2.58 standard deviations under the normal curve.
Given that the standard deviation (σ) is 0.4 ounces, using the formula X = μ + Zσ (where Z is the Z-score corresponding to the desired percentile, μ is the mean we want to find, and X is the threshold value where the cup overflows at 8 ounces), we can substitute the known values and solve for μ.
Therefore, 8 = μ + 2.58 * 0.4 Solving for μ gives us around μ = 7.966, or about 8 ounces. Hence, the mean setting of the coffee machine should be set around 8 ounces to ensure that the cup will overflow only 0.5% of the time.
#SPJ12