If a roof's slope is 0.5, how high will the roof rise over a 17-foot run?a). 8 1/2 feet
b). 17feet
c). 1/34 feet
d). 34 feet

Answers

Answer 1
Answer: The answer to the mathematics question presented above would be letter a) 8 and 1/2 feet. If a roof's slope is 0.5, the height of the rise of the roof over a 17 foot run would be 8 and 1/2 feet. I got this answer through multiplying the slope and the run to get the rise. 
Answer 2
Answer: Answer a) 8 and half feet.

You calculate it in this way

slope = rise / run ⇒ rise = slope * run = 0.5 * 17 feet = 8.5 feet.

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Answers

Answer:

The answer is A

Step-by-step explanation:

You would measure earth's mass is kg and not in g , mg or mcg

Tommy and his dad rode their bikes at a speed of 12 m.h.p. For 2 hours. They rested in a park and rode at 8 m.p.h. For 2 more hours. How many miles did they travel in total?

Answers

40 miles in total that they traveled

Expand the following by using binomial theorem.
I) (7x-4y)⁵​

Answers

(7x-4y)+( 7x-4y)+(7x-4y)+

(7x-4y)+(7x-4y)

if a storm window has an area of 315 square inches what are the dimensions if the window is 6 inches higher than it is wide ( x represents height)?

Answers

Hey there! The formula for area is area=l*w, l=w+6. Let's begin, 315=(w+6)(w), 315=w^2+6w, 0=w^2+6w-315, 0=(w+21)(w-15), w+21=0w-15=0, w=-21w=15. Therefore, we come up with a answer of w=15 and l=21.

Find the sum of the given polynomials.7b + 3, -4b + 5, and -3b + 2

answer options are:
10b + 2
10
0
b - 8

I will give Brainliest answer and a thank you.

Answers

Rearrange the equation for like terms:

7b - 4b - 3b + 3 + 5  + 2

= 10

Answer:

10

Step-by-step explanation:

What proportion of the first 10,000 natural numbers contain a 3

Answers

we know that

It is much easier to compute the number of numbers that do not contain a 3.

In the first 10 numbers 9 do not contain a 3.

In the first 100 numbers 81 do not contain a 3. (This is because these numbers are formed by selecting a digit out of

[0, 1, 2, 4, 5, 6, 7, 8, 9] for the first position and another digit out of the same set for the last position and this may be done in

9*9 = 81 ways.

In the first 1000 numbers, reasoning as above, there are

9^(3) numbers that do not contain a 3.

Now the pattern should be becoming obvious.

In the first 10^(n) numbers there are 9^(n) numbers that do not contain a 3.

So

In the first 10^(4) numbers there are 9^(4) numbers that do not contain a 3.

9^(4)= 6,561

10,000- 6,561= 3,439

Thus

the ratio of those numbers that do contain a 3 over the total is equal to

Ratio=(3,439)/(10,000) \n \n Ratio=0.3439

therefore

the answer is

0.3439

In the first 10 -> 10 - 9 = 1 (contain a 3).
In the first 100 -> 100 - 9 * 9 = 19 (contain a 3).
In the first 10^n -> 10^n - 9^n  (contain a 3).


So for 10^4 -> 10^4 - 9^4 = 10.000 - 6.561 = 3.439

The answer is 3.439 numbers contain a 3 in the first 10.000