What is the factoring quadratic expression for 27x^2-12=0

Answers

Answer 1

Answer: $27x^2-12=0\ /:3\n\n9x^2-4=0\ \ \ \Leftrightarrow\ \ \ (3x)^2-2^2=0\ \ \ \Leftrightarrow\ \ \ (3x-2)(3x+2)=0\n\n3x-2=0\ \ \ \ \ \ \ \ or\ \ \ \ \ \ 3x+2=0\n\n3x=2\ /:3\ \ \ \ \ \ \ or\ \ \ \ \ \ 3x=-2\ /:3\n\nx= (2)/(3) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ x=- (2)/(3)$

Answer 2

Answer: $27x^2-12=0\n 3(9x^2-4)=0\n 3(3x-2)(3x+2)=0\n x=(2)/(3) \vee x=-(2)/(3)$

BELOW

Step-by-step explanation:

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-8,\:-11\right),\:\left(x_2,\:y_2\right)=\left(17,\:4\right)\n\nm=(4-\left(-11\right))/(17-\left(-8\right))\n\nm = (4+11)/(17+8)= (15)/(25) \n\mathrm{Refine}\n\nm=(3)/(5)$

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(10,\:-15\right),\:\left(x_2,\:y_2\right)=\left(13,\:-17\right)\n\nm=(-17-\left(-15\right))/(13-10)\n\nm = (-17+15)/(13-10)\n \nm = (-2)/(3)\n \nSimplify\nm=-(2)/(3)$

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(5,\:-7\right)\n\nm=(-7-\left(-7\right))/(5-\left(-6\right))\n\nm = (-7+7)/(5+6)\n \nm = (0)/(11)\n \nSimplify\nm=0$

10.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-4,\:-3\right),\:\left(x_2,\:y_2\right)=\left(2,\:-9\right)\n\nm=(-9-\left(-3\right))/(2-\left(-4\right))\n\nm = (-9+3)/(2+4)\n \nm = (-6)/(6) \n\nSimplify\nm =-1$

11.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\mathrm{When\:}y_1\ne \:y_2\mathrm{\:and\:}\:x_1=x_2\mathrm{\:the\:slope\:is\:}\infty \n\nm = \infty$

12.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-5,\:3\right),\:\left(x_2,\:y_2\right)=\left(19,\:-6\right)\n\nm=(-6-3)/(19-\left(-5\right))\n\nm = (-6-3)/(19+5)\n \nm = (-9)/(24)\n \nSimplify\nm=-(3)/(8)$

13.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-7,\:-12\right),\:\left(x_2,\:y_2\right)=\left(1,\:-16\right)\n\nm=(-16-\left(-12\right))/(1-\left(-7\right))\n\nm = (-16+12)/(1+7) \n\nm = (-4)/(8) \n\nSimplify\nm=-(1)/(2)$

14.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-18,\:0\right),\:\left(x_2,\:y_2\right)=\left(-13,\:1\right)\n\nm=(1-0)/(-13-\left(-18\right))\n\nm = (1-0)/(-13+18)\n \nm = (1)/(5) \n$

15.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(1,\:-11\right),\:\left(x_2,\:y_2\right)=\left(-2,\:-4\right)\n\nm=(-4-\left(-11\right))/(-2-1)\n\nm = (-4+11)/(-2-1)\n \nm = (7)/(-3) \n\nSimplify\nm=-(7)/(3)$

When creating a scatterplot, if the points are too close together to see the relationship, how could you adjust your graph?A.
decrease your scale values
B.
increase your scale values
C.
plot more points
D.
plot fewer points

Answers

The correct answer for this question is this one: "B. increase your scale values"

When creating a scatterplot, if the points are too close together to see the relationship, You adjust your graph by increasing your scale values
Hope this helps answer your question and have a nice day ahead.

Answer:

Option: B is correct.

B) Increase your scale values.

Step-by-step explanation:

When creating a scatterplot, if the points are too close together to see the relationship,then we must increase the scale value of our graph .

" Because by doing so the point will seem to be farther and we could see the clear relationship between the points and hence it will not create any confusion regarding the visual of the points and hence easily the inference could be drawn"

Hence, option: B is true.

(B) Increase the scale value)

Plz help .......................

Answers

$( 6√(2))/( √(3) )$

Multiply the square root of 3 by the square root of 2 and itself.
The 3 cancels itself out and then you get A

Brainliest first correct answer!

Answers

Answer:

Step-by-step explanation:

Which of the following correctly completes the square for the equation below?x^2+2x=19
a. (x+2)^2=20
b. (x+1)^2=23
c. (x+1)^2=20
d. (x+2)^2=23

Answers

Answer:

c. $(x+1)^2=20$

Step-by-step explanation:

Since, for getting a perfect square on the left side of a quadratic equation we follow the following steps,

Step 1 : Make 1 as the coefficient of $x^2$ .

Step 2 : Add both side the square of a number which is half of the x's coefficient.

Given equation,

$x^2+2x=19$ -----(1)

Here, the coefficient of $x^2$ is already one.

And, the middle term is 2,

Half of 2 is 1

Also, 1² = 1

Thus, add 1 on both sides of equation (1),

$x^2+2x+1 = 19 + 1$

$(x+1)^2 = 20$ ( Because (a+b)² = a² + 2ab + b² )

⇒ Option C is correct.

The answer is :

c. (x+1)²=20

To check:
(x+1)²=20 (a+b)²=a²+2ab+b²
x²+2x+1=20
x²+2x=20-1
x²+2x=19

point v is located at (-2,6) on the coordinate plane. Point V is reflected over the y-axis to create point V Poinr v is then reflected over the x axis to create point V What ordered pair describes the location of V

Answers

Shouldn’t it be (2,-6), might be wrong. All points can be Point V, else they’ll be the same (I’m in geo only).

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What is the factoring quadratic expression for 27x^2-12=0

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