The class of 2015 decides to start a T-shirt company. After initial expenses of $280, the purchase each t-shirt for $3.99. They sell each t-shirt for $10.99. how many must they sell to break even?

The cost or amount of money spent on the salmon fish of 8 ounces is 8.99 dollars.

How to find cost of the fish?

She buys 8 ounces of smoked salmon at $17.98 per pounds .

Therefore lets convert ounces to pounds.

16 ounces = 1 pounds

She buys the fish at $17.98 per pounds.

Therefore,

16 ounces = 1 pounds

8 ounces = 0.5 pounds

Hence,

1 pounds =  $17.98

0.5 pounds = ?

cross multiply

cost of 8 ounces of the salmon fish  = 0.5 × 17.98 = $8.99

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The correct answer is:

contains a table with a logical series of statements and reasons that reach a conclusion.  

Explanation:

In a two-column proof, our two columns are "statements" and "reasons."

In the "statements" column, we write the different steps that take us from our given to the statement we are trying to prove.

In the "reasons" column, we write the theorems, postulates, and definitions that we need to justify the steps taken in the "statements" column.

Answer:

the answer is B contains a table with a logical series of statements and reasons that reach a conclusion.

Step-by-step explanation:

Answer:

all of em

Step-by-step explanation:

Answer:

The common difference d is larger than the common ratio r

Step-by-step explanation:

• The common difference in the arithmetic sequence  

• The nth term in the arithmetic sequence is , where a is the first term

• The common ratio in the geometric sequence

• The nth term in the geometric sequence is , where a is the first term

Geometric sequence

∵ The second term is 24

∴ = 24

∵

- Equate it by its value

∴ ar = 24 ⇒ (1)

∵ The fifth term is 1536

∴   = 1536

∵

- Equate it by its value

∴ = 1536 ⇒ (2)

Divide (2) by (1)

∴

- Divide up and down by ar

∴ r³ = 64

- Take ∛  for both sides

∴ r = 4

Arithmetic sequence

∵ The fourth term is 16

∴ = 16

∵ = a + (4 - 1)d

∴ = a + 3 d

- Equate it by its value

∴ a + 3d = 16 ⇒ (1)

∵ The seventh term is 31

∴ = 31

∵ = a + (7 - 1)d

∴ = a + 6 d

- Equate it by its value

∴ a + 6 d = 31 ⇒ (2)

Subtract equation (1) from equation (2) to eliminate a and find d

∵ (a - a) + (6 d - 3 d) = (31 - 16)

∴ 3 d = 15

- Divide both sides by 3

∴ d = 5

∵ r = 4 and d = 5

∴ d > r

∴ The common difference d is larger than the common ratio r