5x − 3y = 0
B.
-x + 3y = 0
C.
-5x − 3y = 0
D.
3x + 5y = 0
E.
-3x + 5y = 0
Answer:
3y + 5x = 0
Step-by-step explanation:
The slope of the line = (y2-y1) / (x2-x1) = (5-0)/(-6-(-3))
= 5 / -3 = -5/3
Using the point-slope form , the line that passes through the origin and parallel to this line is
y - 0 = -5/3(x - 0)
y = -5/3 x
Multiply through by 3:-
3y = -5x
5x + 3y = 0
To use the distributive property to state 28*63, we break down 28 into two smaller numbers say 20 and 8, and then multiply each by 63 and add the products. So, 28*63 is (20*63)+(8*63), which is 1764.
The problem is asking you to use the distributive property to rewrite the multiplication 28*63. The distributive property is about breaking down larger numbers into smaller, manageable parts. Now, this involves a strategy of breaking down the numbers.
Let's break down the number 28 into 20 and 8. So, the multiplication could be rewritten as (20 + 8) * 63.
Now apply the distributive property (also known as Distributive Law of Multiplication) which states that multiplying a number by a sum of two numbers is equivalent to multiplying the number individually by each of the numbers and then adding the products together.
So, (20 + 8) * 63 equals (20*63) + (8*63)
The final answer to the equation would be (20*63) + (8*63) = 1260 + 504 = 1764.
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The value of labor cost as a percentage of Revenue is, 32%.
A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.
To Calculate the percent of a number , divide the number by whole number and multiply by 100.
We have to given that;
The Revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40 hours each.
Now,
The total labor cost for 2 workers = 2 × 8 × 40
= $640
Hence, The value of labor cost as a percentage of Revenue is,
⇒ (640/2000) x 100
⇒ 64 / 2
⇒ 32%
Therefore, We get;
The value of labor cost as a percentage of Revenue is,
⇒ 32%
Learn more about the percent visit:
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a = 16, b = 29, c = 22, d = 30, e = 24
a = 29, b = 16, c = 30, d = 22, e = 24
a = 16, b = 29, c = 24, d = 22, e = 30
a = 29, b = 16, c = 24, d = 30, e = 22
Let x be the number of students that like both algebra and geometry. Then:
1. 45-x is the number of students that like only algebra;
2. 53-x is the number of students that like only geometry.
You know that 6 students do not like any subject at all and there are 75 students in total. If you add the number of students that like both subjects, the number of students that like only one subject and the number of students that do not like any subject, you get 75. Therefore,
x+45-x+53-x+6=75.
Solve this equation:
104-x=75,
x=104-75,
x=29.
You get that:
The correct choice is D.
It is very easy to find the values for a, b, c, d and e. All you have to do is use the Algebra vs. Geometry table to use the given values to find the rest. Please see attachment to see the table. For example if we want to find e we simply subtract 53 from 75. This way e = 22, then use this to find the next value which will be b.
The answer is:
a = 29, b = 16, c = 24, d = 30 and e = 22
I hope this helps, Regards.