Answer:
The percent yield of this reaction is 92.7 %
Explanation:
Step 1: Data given
Mass of nitrogen gas (N2) = 34.0 grams
Mass of ammonia (NH3 produced = 41.0 grams
Molar mass of N2 = 28.0 g/mol
Molar mass of NH3 = 17.02 g/mol
Actual yield of ammonia = 38 grams
Step 2: The balanced equation
N2(g) + 3H2(g) → 2NH3(g)
Step 3: Calculate moles
Moles = mass / molar mass
Moles N2 = 34.0 grams / 28.0 g/mol
Moles N2 = 1.214 moles
Step 4: Calculate moles NH3
For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3
For 1.214 moles N2 we'll have 2* 1.214 = 2.428 moles NH3
Step 5: Calculate mass NH3
Mass NH3 = moles * molar mass
Mass NH3 = 2.428 moles * 17.02 g/mol
Mass NH3 = 41 grams
Step 6: Calculate percent yield for the reaction
Percent yield = (actuald yield / theoretical yield) * 100 %
Percent yield = (38 grams / 41 grams ) * 100 %
Percent yield = 92.7 %
The percent yield of this reaction is 92.7 %
Answer:
Explanation:
Hello,
In this case, by considering the given chemical reaction, with given mass of nitrogen, one could compute the theoretical yield of ammonia as shown below and considering their 1 to 2 molar relationship in the chemical reaction:
In such a way, the percent yield is obtained as shown below:
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plz help
Explanation:
General Rules. In general, the electropositive character of the oxide's central atom will determne whether the oxide will be acidic or basic. The more electropositive the central atom the more basic the oxide. The more electronegative the central atom, the more acidic the oxide.
1
There are six liquids found on the periodic table.
1. Bromine
2. Mercury
3. Caesium
4. Gallium
5. Rubidium
6. Francium
Answer:
the awnser is minerals :)
Explanation:
just took the test on edg.