it takes a hose 4 minutes to fill a rectangle 9inc long, 11inches wide and 12 inches tall, how long will it take to fill an aquarium 24 by 25 by 33 inches tall

Answers

Answer 1
Answer: OK the problem is focusing on VOLUME and TIME.. you can set up this problem like this... (v1/t1) x (v2/t2). first we plug in what we know. the first container was filled in 4 minutes so this is our "T1". However we weren't giving the volume of the first container but we were given its dimensions. the volume formula is LxWxH. so we plug in 9x11x12 to get 1188. this is our "V1". the same concept applies for the volume of the aquarium. we have its dimensions so just plug in. 24x25x33 = 19800 this is our "V2". the thing we are left trying to find is T2. so now you can do some cross multiplying and division. (T1xV2)/V1 or (4x19800)/1188 and you get 66.67min or 1h and 6.67mins. and thats how long it took to fill the aquarium.

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If Joel’s family starts with a full tank of gas, can they drive the car for 15 days without the warning light coming on?

Answers

Answer:

Yes they can drive for 15 days without the light

Step-by-step explanation:

If its 0.5 gass each day 0.5 gas ×15days that would be 7.5

1 over 3 +2over 5) x 2 over 3

Answers

1/3 + 2/5 • 2/3

2 • 2 = 4
5 • 3 = 15

1/3 = 5/15

5/15 + 4/15 = 9/15 = 3/5

1/3 + 2/5 • 2/3 = 3/5

Whats the least common factor of 20,44,88

Answers

The least common factor of any group of whole numbers is ' 1 '.

The greatest common factor of those three numbers is  4 .

A trailer is rented at $30 per day plus a charge per mile of use. The trailer traveled 25 miles in one day, and the total charge was $130. Which equation can be used to find the charge x, in dollars, per mile traveled?30x + 25 = 130

30x + 25x = 130

30 + 25x = 130

30 + 25 = 130x

Answers

30+25x=130 is the corresponding equation

Karyn cuts the length of a ribbon into 4 equal pieces. each 1 1/4 feet long. How long was the ribbon?

Answers

5 feet. 1*4 is four and 1/4 * 4 is 1 added together that is 5

Answer: you add 1 1/4, 4 times which equals 4 4/4 or 5

Step-by-step explanation:

If triangle RST is congruant to triangle ABC, the measure of angle A equals x^2-8x, and the measure of angle C equals 4x-5, and the measure of angle R equals 5x+30 find the measure of angle C [ only an algebraic solution can receive full credit.]

Answers

In any statement like this one: \triangle RST \cong \triangle ABC you can assume that the points match up in the order that you are given them.
This means that \angle A \cong \angle R.
We know that m\angle A = x^2-8x and m\angle R=5x+30, and because they are congruent we can set the two equal to each other.

x^2-8x=5x+30
Let's get everything to one side.
x^2-13x-30=0
Let's solve by factoring, since it's easy to do with these whole numbers.
We're looking for two number thats add to -30 and multiply to -13...
These would be -15 and 2.
Since our leading coefficient (_x²) is 1, we can factor straight to (x-15)(x+2).
Here's what it would look like if you went through all the steps anyways, though.
x^2-15x+2x-30=0
x(x-15)+2(x-15)=0
(x+2)(x-15)=0
Any value which causes either factor to equal 0 is a solution.
(The second factor wouldn't matter b/c 0 times anything is still 0)
Therefore x = -2 or 15.
Only one of these is possible, however!
If you use x = -2, you will find that the angle measure 4x-5 is negative, which is impossible. In this case, x must be 15.

Let's find the measure of angle C.
m\angle C=4x-5\ where\ x=15\nm\angle C=4(15)-5\nm\angle C=60-5\n\boxed{m\angle C = 55\°}
             ΔRST ≡ ΔABC
      
           <R = <A
       (5x + 30)° = (x² - 8x)°
          5x + 30 = x² - 8x
  -x² + 5x + 30 = x² - x² - 8x
  -x² + 5x + 30 = -8x
      + 8x           + 8x
-x² + 13x + 30 = 0
x = -(13) ± √((13)² - 4(-1)(30))
                       2(-1)
x = -13 ± √(169 + 120)
                    -2
x = -13 ± √(289)
             -2
x = -13 ± 17
           -2
x = -13 + 17    U    x = -13 - 17
           -2                           -2
x = 4    U    x = -30
     -2                 -2
x = -2         x = 25

<C = 4x - 5       U    <C = 4x - 5
<C = 4(-2) - 5    U    <C = 4(25) - 5
<C = -8 - 5        U    <C = 100 - 5
<C = -13°          U    <C = 95°

or

          ΔRST ≡ ΔABC
      <A + <C = <R
     (x² - 8x)°+ (4x - 5)° = (5x + 30)°
       (x² - 8x) + (4x - 5) = (5x + 30)
         (x² - 8x + 4x - 5) = (5x + 30)
                   x² - 4x - 5 = 5x + 30
                      - 5x       - 5x        
                   x² - 9x - 5 = 30
                             - 30 - 30
                 x² - 9x - 35 = 0
x = -(-9) ± √((-9)² - 4(1)(-35))
                       2(1)
x = 9 ± √(81 + 140)
                  2
x = 9 ± √(221)
              2
x = 9 ± 14.86
              2
x = 9 + 14.86   U    x = 9 - 14.86
             2                            2
x = 23.86    U    x = -4.14
         2                        2
x = 11.93    U    x = -2.07