Giselle graphs the function f(x) = x^2. Robin graphs the function g(x) = –x^2. How does Robin’s graph relate to Giselle’s?Robin’s graph is a reflection of Giselle’s graph over the x-axis.
Robin’s graph is a reflection of Giselle’s graph over the y-axis.
Robin’s graph is a translation of Giselle’s graph 1 unit down.
Robin’s graph is a translation of Giselle’s graph 1 unit left.

Answers

Answer 1
Answer: The first one is the answer.

Sketch the graph of the two by substituting x as 1, 2, 3 and you will see that the two graphs look exactly the same but seem to be reflected through the mirror line of the x-axis
Answer 2
Answer:

Answer:

First Option

Step-by-step explanation:


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A circle is shown. A secant and a tangent intersect at a common point outside of the circle to form an angle that measure 51 degrees. The measure of the first arc formed is x degrees and the measure of the second arc formed is 160 degrees.What is the value of x?

x =

Answers

The value of x in the circle is 58°

Secant and tangent intersection

when a secant and a tangent meets outsides of a circle, the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs. Therefore,

51° = 1 / 2 (160 - x)

Therefore,

51 = 80 - x / 2

51 - 80 = - 1 /2 x

-29 = - 1 / 2 x

multiply both sides by -2

-29 ×  2 = - 1 / 2 x × -2

x = 58

Therefore, the value of x is 58 degrees

learn more on secant and tangent here;brainly.com/question/14697178

Answer:

58

Step-by-step explanation:

just did it on edg

A study is done on the population of a certain fish species in a lake. Suppose that the population size P(t) after t years is given by the following exponential function. P(t)=280(1.29)^t Find the initial population size?
does the function represent growth or decay?
By what percentage does the population change each year?

Answers

Answer:

  1. 280
  2. function represent growth.
  3. 29 %

Step-by-step explanation:

Equation to calculate population size after time, t

P(t) = 280(1.29)^t

To find initial population size we will take t = 0

P(0) = 280(1.29)^0

       = 280(1)

       = 280

To find that function represent growth or decay

P(1) = 280(1.29)^1

      = 280(1.29)

      = 361.2

Its means that after a year population increases. Hence, function represent growth.

By what percentage does the population change each year?

(361.2 - 280 / 280) * 100%

 = 29 %

Answer:

280

function represent growth.

29 %

The volume of a hemisphere is 144 pi. Find the radius and total surface area.

Answers

Formula of the Volume of a hemisphere:
V = (2)/(3)\pi
144\pi(2)/(3)\pi
Multiply by 3 to cancel fraction in the right side
144\pi × 3 = 2\pi
432 \pi = 2\pi
Divide by 2\pi on either sides to isolate r³
(432 \pi )/(2 \pi )(2 \pi )/(2 \pi )
2\pi and 2 \pi cancel out
216 = r³
Take cube root to find the radius
\sqrt[3]{216}\sqrt[3]{r^3}
6 = r
Radius is 6 units

The formula of the surface area of a hemisphere is:
S.A = 2\pir² + \pi
       = 2\pi(6)² + \pi(6)²
       =2\pi × 36 + 36\pi
       = 72\pi + 36\pi
       = 108\pi units²  (in terms of \pi)
       ≈ 339.12 units²

Surface area = 108\pi units

How many diagnals can you draw from a single vertex of a 35-gon?

Answers


Well let's see.  Your -gon has 35 vertexies.  You use one of them
to start all the diagnals from.  That leaves (35 - 1) = 34 others
that could be the other end of a diagnal. 

So there must be 34 possible diagnals.

Which of the following accurately shows the range of the function defined below?

Answers

Answer: The answer is (b) (2, ∞)

Step-by-step explanation:  We are given a function f(x) in the figure and we are to select out of the given options that accurately shows the range of the function defined.

\textup{For }x < 0, \textup{we have}~f(x)=3.

\textup{For }0\leq x<2,\textup{ we have }f(x)=x^2+2\geq 2.

\textup{For }x\geq 2,\textup{ we have }f(x)=(1)/(2)x+5\geq 5.

Therefore, the range of the function f(x) will be greater then or equal to 2. So, the range will be [2, ∞).

Thus, the correct option is (b) (2, ∞).

Answer:
it's b

Step-by-step explanation:

Kiara has a ribbon that measures 1/4 of an inch and Jillian has a ribbon that measures 2/3 of an inch. Jillian says their ribbons are equal in length because her numerator is one more than kiara's and her denominator is one less, therefore balancing the two fractions. Is she correct? Why or why not?

Answers

Answer:

Jillian is Incorrect as fraction can never be balanced based on numerator or denominator.

Step-by-step explanation:

Given:

Measure of ribbon Kiara has = (1)/(4) \ inch

Measure of ribbon Jillian has = (2)/(3) \ inch

Now given:

Jillian says their ribbons are equal in length because her numerator is one more than kiara's and her denominator is one less, therefore balancing the two fractions.

we need to find whether statement is correct or not.

First we will find the decimal value of the given fraction's

(1)/(4) \ inch can rewritten as 0.25\ inch

Measure of ribbon Kiara has = 0.25 inch

(2)/(3) \ inch can be Rewritten as 0.67\ inch

Measure of  ribbon Jillian has = 0.67 inch

Now we can see that;

0.67 inch is greater than 0.25 inch.

Hence we can say that ribbons are not in equal length.

Also the fraction can never be balanced by decreasing or increasing the numerator or denominator.