Answer:
it is 66 pounds
fraction 7 over 50
fraction 8 over 50
fraction 1 over 7
fraction 2 over 7
Answer:
To determine how many 7 over 10s are there in 1 over 5, we need to compare the two fractions and find their relationship.
Given:
7 over 10 represents the shaded portion in a rectangle divided into 10 equal portions, with 7 portions shaded.
1 over 5 represents the shaded portion in a rectangle divided into 5 equal portions, with 1 portion shaded.
To find the relationship between these two fractions, we can compare the number of shaded portions in each rectangle.
Since there are 7 shaded portions out of 10 in the first rectangle and 1 shaded portion out of 5 in the second rectangle, we need to determine how many times the shaded portion in the first rectangle fits into the shaded portion in the second rectangle.
To find this, we can set up a proportion:
7/10 = x/1
Cross-multiplying, we get:
10x = 7
Solving for x, we divide both sides by 10:
x = 7/10
Therefore, there are 7 over 10s in 1 over 5.
14
16
17
Answer:
38
Step-by-step explanation:
The outlier of the data set is defined as the data point which lies outside the overall given data set.
Now, the given set is:
17, 13, 16, 18, 38, 14, 21, 24, 38, 14, 16, 17
Now, we can see from the given set that 38 lies outside overall given data set, therefore according to the definition of an outlier, 38 is an outlier.
Margo’s wires measure 6 inches, 8 inches, and 14 inches.
Sonji’s wires measure 12 inches, 8 inches, and 17 inches.
Liam’s wires measure 16 inches, 8 inches, and 27 inches.
Which student chose pieces that can be used to construct a triangle?
Don
Margo
Sonji
Liam
Answer:
Sonji
Step-by-step explanation:
Given :
We will use the third important property of triangles is the triangle inequality rule, which states: the length of a side of a triangle is less than the sum of the lengths of the other two sides and greater than the difference of the lengths of the other two sides.
So, applying this property in each case:
Case 1. Don’s wires measure 3 inches, 5 inches, and 12 inches.
Now using property
since sum of two sides = 3+5 =8
But third side 12 is not less than 8
So, Don’s wire cannot be used .
Case 2. Margo’s wires measure 6 inches, 8 inches, and 14 inches.
Now using property
since sum of two side :8+6=14
But third side 14 is not less than 14
So, Margo’s wire cannot be used .
Case 3. Sonji’s wires measure 12 inches, 8 inches, and 17 inches.
Now using property
since sum of two side :12+8=20
third side 17 is less than 20
Now , difference of two sides : 12-8=4
third side 17 is greater than 4
So, Sonji’s wire can be used .
Case 4. Liam’s wires measure 16 inches, 8 inches, and 27 inches.
Now using property
since sum of two side :16+8 =24
But third side 27 is not less than 24
So, Liam’s wire cannot be used .
Hence sonji's wire can be used to construct a triangle
300
1:1
1*300:1*300
300:300
Whenever the two numbers in a ratio are the same it means that they're equal. Hope this helps :)