Which scenario best matches the linear relationship expressed in the equation y = 32x + 80?Joseph has $80 in his bank account and spends $32 each day.
Joseph has $80 in his bank account and earns $32 each day.
Joseph had $32 in his bank account and deposited another $80.
Joseph has $32 in his bank account and earns $80 each day.

Answers

Answer 1
Answer:

Answer:

Option (2) best matches the given the linear relationship y = 32x + 80

Step-by-step explanation:

Given linear relationship as  y = 32x + 80

We have to find the best match from the given options to the given the linear relationship.

1) Joseph has $80 in his bank account and spends $32 each day.

Let the money Joseph spend each day be $x

Since, the amount one spend gets deducted from the money one have.

So, given statement is represented as y = 80 - 32x .

2) Joseph has $80 in his bank account and earns $32 each day.

Let the money Joseph earns each day be $x

Since, the amount one earns gets added to the money one have.

So, given statement is represented as y = 80 + 32x .

3) Joseph had $32 in his bank account and deposited another $80.

Since, he is depositing money in account so it gets add up

So, given statement is represented as  y = 32 + 80 = 112

4) Joseph has $32 in his bank account and earns $80 each day.

Let the money Joseph earns each day be $x

Since, the amount one earns gets added to the money one have.

So, given statement is represented as y = 32 + 80x .

Out of all four option, option (2) best matches the given the linear relationship y = 32x + 80

Answer 2
Answer: he has 80 in the bank account and earns 32 each day....where x represents the number of days and y represents the total in the account

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8 cm
16 cm
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Answers

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I need this TONIGHT!!! Three years ago, Jolene bought $750 worth of stock in a software company. Since then the value of her purchase has been increasing at an average rate of 5 1/2% per year. How much is the stock worth now? (Round each money calculation you make to the nearest cent.) The stock is worth $ now.

Answers

Answer:

A\approx\$880.68

Step-by-step explanation:

So, we know that Jolene bought an initial $750.

We also know that the purchase is increasing at an average rate of 5 1/2 %or 5.5%. In other words, this is being compounded.

So, we can use the compound interest formula, which is:

A=P(1+(r)/(n))^(nt)

Where A is the total amount, P is the principal value, r is the rate and n is the number of times compounded per year, and t is the amount of years.

So, substitute 750 for P. 5 1/2% is the same as 5.5% or 0.055 (you move the decimal two places to the left and remove the percent symbol) so substitute this for r. Since it's increasing yearly, n is 1. So, our formula is:

A=750(1+0.055)^t

Add:

A=750(1.055)^t

Since the stock was bought 3 years ago, the value now is t=3. So, substitute 3 for t and evaluate:

A=750(1.055)^3

Evaluate. Use a calculator:

A\approx\$880.68

And we're done!

Formula: A = P(1 + r/n)^t

We have these variables:

P = 750

r/n = 0.055

t = 3

Substitute and simplify:

A = 750(1 + 0.055)^3

A = 750(1.055)^3

A = 880.68

Best of Luck!

Kathy lives directly east of the park. The football field is directly south of the park. The library sits on the line formed between Kathy's home and the football field at the exact point where an altitude to the right triangle formed by her home, the park, and the football field could be drawn. The library is 9 miles from her home. The football field is 12 miles from the library.a. How far is the library from the park?
b. How far is the park from the football field?

Answers

see the attached figure to better understand the problem

Let

z---------> distance from the library to the park in miles

x-------> distance from the park to the to the football field in miles

y-------> distance from the park to Kathy's home in miles

we know that

In the right triangle ABC

Applying the Pythagorean Theorem

x^(2) +y^(2) =(12+9)^(2) \n x^(2) +y^(2)=441 -----> equation 1

In the right triangle ABD

Applying the Pythagorean Theorem

12^(2) +z^(2) =x^(2) \n 144 +z^(2)=x^(2) -----> equation 2

In the right triangle BCD

Applying the Pythagorean Theorem

9^(2) +z^(2) =y^(2) \n 81 +z^(2)=y^(2) -----> equation 3

Add equation 2 and equation 3

144 +z^(2)=x^(2)

81 +z^(2)=y^(2)\n ------

144+81+2z^(2) =x^(2) +y^(2) -----> equation 4

Substitute equation 1 in equation 4

144+81+2z^(2)=441\n 2z^(2) =441-225\n 2z^(2)=216\n z^(2)=108\n z=√(108) miles\n z=10.39 miles

Find the value of x

144 +z^(2)=x^(2)\n 144 +√(108)^(2)=x^(2) \n x^(2) =144+108\n x^(2) =252\n x=√(252) miles\n x=15.87 miles

therefore

the answer is

Part a) The distance from the library to the park is equal to 10.39 miles

Part b) The distance from the park to the to the football field is equal to 15.87 miles

Look at the picture in the attachment.

Using the Pythagorean theorem, set up a system of three equations:
x^2+y^2=(12+9)^2 \n12^2+z^2=x^2 \n9^2+z^2=y^2 \n \nx^2+y^2=441 \n144+z^2=x^2 \n81+z^2=y^2

\hbox{substitute } 144+z^2 \hbox{ for } x^2 \hbox{ and } 81+z^2 \hbox{ for } y^2 \hbox{ in the first equation:} \n144+z^2+81+z^2=441 \n225+2z^2=441 \n2z^2=441-225 \n2z^2=216 \nz^2=(216)/(2) \nz^2=108 \nz=√(108) \nz=√(36 * 3) \nz=6√(3) \n z \approx 10.39

81+z^2=y^2 \n81+108=y^2 \n189=y^2 \n√(189)=y \n√(9 * 21)=y \ny=3√(21) \n y \approx 13.75

a. The library is approximately 10.39 miles (exactly: 6√3 miles) from the park.
b. The park is approximately 13.75 miles (exactly: 3√21 miles) from the football field.

What is the closed linear form of the sequence of the negative even integers starting with -2?A) an = 2n
B) an = -2n
C) an = -2 - n
D) an = -2 + 2n

Answers

Hello,


n=1,2,3,.... and not 0

Answer B a(n)=-2*n

Answer: It's B i did usa test prep and got it right

Step-by-step explanation:

For the function f(x) = 2(8)^x evaluate f(2)

Answers

Answer:

f(2)=128

Step-by-step explanation:

f(x) = 2(8)^x evaluate f(2)

f(2)= 2(8)^2

f(2)=2(64)

f(2)=128

True or false: Polar equations can describe graphs as functions, even when their equations in the rectangular coordinate system are not functions.

Answers

The statement above is true. Polar equations indeed can describe graphs as functions, even if when the equations in the rectangular coordinate system are not one of the functions. Polar equations can be graphed accurately using hands by using the Polar Coordinate System.

Answer:

The answer is true.

Step-by-step explanation:

A polar equation describes the relation between r and θ. Here 'r' is the distance from the origin to a point curve. 'θ' is the angle made by a point on a curve, the pole, and the positive x-axis.

So, the statement - Polar equations can describe graphs as functions, even when their equations in the rectangular coordinate system are not functions - is true.