Which example describes constant acceleration due ONLY to a change in direction?a. increasing speed while traveling around a curve
b. an object at rest
c. traveling around a circular track
d. an object in free fall

Answers

Answer 1
Answer:

Answer:

c. traveling around a circular track

Explanation:

Acceleration is defined as the rate of change of velocity per unit time:

a=(\Delta v)/(\Delta t)

However, velocity is a vector quantity. This means that acceleration can be due to:

- A change in the speed of an object, or

- A change in the direction of the object

Let's analyze each choice:

a. increasing speed while traveling around a curve  --> in this case, both speed and direction are changing (the direction is changing since the object is moving around a curve), so this is not the correct choice

b. an object at rest  --> here neither the speed nor the direction are changing (in fact, the object is not accelerating), so this is not the correct choice

c. traveling around a circular track  --> here the direction is changing (because the track is circular), while we don't know anything about the speed. If we assume the speed to be constant, then this is the correct choice

d. an object in free fall --> here the speed is changing, while the direction not, so this is not the correct choice

Answer 2
Answer:
'Traveling around a circular track' can be a description of constant
acceleration due only to changes in direction.  But if it is, then the
progress around the circular track must be at constant speed.


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If an astronaut weighs 750 N on the ground, what will he weigh in earth orbit 400 km above the earth’s surface? R_earth = 6.38 × 10^6 m,
m_earth=5.97×10^24 kg
G=6.674×10^−11 Nm^2/kg^2

Answers

Answer:

The weight of the astronaut in Earth's orbit 400 km above the Earth's surface is 664.115 N

Explanation:

The given parameters are;

The weight of the astronaut on the ground = 750 N

The height of the orbit above the Earths surface = 400 km

The radius of the Earth = 6.38 × 10⁶ m

The mass of the Earth = 5.97 × 10²⁴ kg

The universal gravitational constant G = 6.674 × 10⁻¹¹ Nm²/kg²

From Newton's law of universal gravitation, we have;

Weight \ on \ ground \ of \ astronaut \ F_W =G* (M_(Earth) * m_(astronouat))/(R_(Earth)^(2)) = 750 \ N

F_W =6.674 * 10^(-11)* (5.97 * 10^(24)* m_(astronouat))/((6.38 * 10^6)^(2)) = 750 \ N

m_(astronaut) = ((6.38 × 10⁶)² × 750)/((6.674 × 10⁻¹¹) × (5.97 × 10²⁴)) ≈ 76.62 kg

The mass of the astronaut ≈ 76.62 kg

For the weight of the astronaut  in Earth orbit 400 km (400 × 10³ m) above the Earth's surface, we have;

F_(W \ in \ orbit) =6.674 * 10^(-11)* (5.97 * 10^(24)* 76.62)/((6.38 * 10^6 + 400 * 10^3)^(2) ) = 664.115 \ N

The weight of the astronaut in Earth's orbit 400 km above the Earth's surface = 664.115 N.

Friction always acts in a direction ______ to the direction of motion.a. equal
c. perpendicular
b. opposite

Answers

Answer:

b.Opposite

Explanation:

Friction: It is that force which oppose the motion of any object.It is rubbing force.

We have to fill given blank space

Friction always act in opposite direction of motion.

Friction force is applied to overcome the motion of object.

If equal friction force applied in opposite direction  to   applied force on the object due to which an object in motion  then the object will come to in rest.

When applied force is not equal to friction force then motion will not come in rest and continue move.

Hence, friction force always acts in a direction opposite to the direction of motion.

Answer : b.Opposite

Friction always acts in a direction opposite to the direction of motion

Timmy bikes to school 3 kilometers east and 2 kilometers south. What is Timmy's final displacement?

Answers

Answer:

3.6km South East

Explanation:

Displacement is the shortest distance between the starting point and the ending point and the direction it is displaced in. To calculate the displacement we can use the pythagoras theorem because the 3km East and the 2km south form the two shorter sides of a right angled triangle between the starting and ending points. So, the displacement is the length C of the triangle which we can calculate as follows:

Pythagoras Theorem:

a^2+b^2=c^2

(2)^2+(3)^2=c^(2)

4+9=c^2

Square root 13 = c

c=3.6km (1dp)

The total displacement is 3.6km and is in the approximate direction of South East (because he travelled east and south).

Hope this helped!

Which action is taken by an offensive player in the game of lacrosse

Answers

Catching or Hitting are the offense players choices 

A 15-kg bicycle carrying a 50-kg boy is traveling at a speed of 5 m/s. What is the KE of the bicycle and the boy?

Answers

Together as one moving package, their mass is (15 + 50) = 65 kg.

       Kinetic energy = (1/2) (mass) (speed)²

                               = (1/2) (65 kg) (5 m/s)²

                               =  (32.5 kg) (25 m²/s²)

                               =     812.5  kg-m²/s²  =  812.5 joules .

Which project involved the goal of orbiting a manned spacecraft around earth? A. Mercury

B. Apollo

C. Gemini

D. Skylab

Answers

A. Mercury
Project Mercury was designed to send a person into orbit before the Soviet Union did so.

Answer:

The anser is A. Mercury

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