A spacecraft is fueled using hydrazine (N2H4; molecular weight of 32 grams per mole [g/mol]) and carries 1640 kilograms [kg] of fuel. On a mission to orbit a planet, the fuel will first be warmed from −186 degrees Fahrenheit [°F] to 78 degrees Fahrenheit [°F] before being used after the long space flight to reach the planet. The specific heat capacity of hydrazine is 0.099 kilojoules per mole kelvin [kJ/(mol K)]. If there is 300 watts [W] of power available to heat the fuel, how long will the heating process take in units of hours [h]?
Answers
The expression for thermal energy and power we were able to find the time necessary to heat the fuel is t = 689 h
To find
- Time
The international measurement system (SI) establishes the fundamental units in the measurement processes, this is defined by convention, giving uniformity in the calculation process and measurement exchange. Before starting the exercise we must reduce the magnitude to the SI system
PM = 32 g / mol ( g) = 32 10-3 kg / mol
T₀ = 5/9 (ºF -32) + 273.15 = 5/9 (186 32) +273.15 = 152.0 K
T_f = 5 * (78 - 32) +273.15 = 298.7 K
c_e = 0.099 kj / mol k () = 0.099 10³ J / mol K
The mole is the amount of matter of the international system (SI), the moles exist must be calculated since they are the mass of the compound for this we use a direct rule of proportions, if a mole has more than 32 10⁻³ kg, when moles are 1640 kg
n =
n = 1640/32 10⁻³
n = 51.25 10³ mol
If we assume that all energy transfer is thermal, we can use
Q =
Q = 51.25 10³ 0.099 10³ (298.7 -152.0)
Q = 7.44 10⁸ J
Power defined by the relationship between work and time
P =
In this case the thermal work is equal to the heat ( W=Q)
t =
t = 7.44 10⁸ / 300
t = 2.48 10⁶ s
They indicate that the answer is given in hours, let's reduce the time
t = 2.48 106 s (1h / 3600s)
t = 6.89 10² h
In conclusion, with the relationship of thermal energy and power, we were able to set the time necessary for the amount of fuel to be t = 689 h
Learn more about thermal energy and power here:
Answer:
The value is
Explanation:
From the question we are told that
The molar mass of hydrazine is
The initial temperature is
The final temperature is
The specific heat capacity is
The power available is
The mass of the fuel is
Generally the number of moles of hydrazine present is
=>
=>
Generally the quantity of heat energy needed is mathematically represented as
=>
=>
Generally the time taken is mathematically represented as
=>
=> t = 2480505.6377 s
Converting to hours
=>
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B. Sour liquid (pH of 5) = acidic
C. Solution with four times as many hydronium (H+) ions as hydroxide ions (OH-) = acidic
Soapy solution with a pH of 9 is basic because it has a pH greater than 7. The same goes for the sour liquid with a pH of 5, which has a pH lower than 7, making it acidic. The word sour also hints at it being acidic because of the definition of Bronsted acids. Finally, higher H+ ion concentrations make a solution more acidic.
B. The original pattern of the light is preserved.
C. The angle of reflection is less than the angle of incidence.
D. The angle of reflection is greater than the angle of incidence.
Answers
whats the magnitude in N ?
(b) Find the centripetal acceleration of the electron.
whats the magnitude in m/s2
Answers
the electron and proton, and then we need to know the electron's mass.
I'm beginning to get the creepy feeling that, in return for the generous
5 points, you also want me to go and look these up so I can use them
in calculations ... go and collect my own straw to make the bricks with,
as it were.
Ok, Rameses:
Elementary charge . . . . . 1.6 x 10⁻¹⁹ coulomb
negative on the electron
plussitive on the proton
Electron rest-mass . . . . . 9.11 x 10⁻³¹ kg
a). The force between two charges is
F = (9 x 10⁹) Q₁ Q₂ / R²
= (9 x 10⁹ m/farad) (-1.6 x 10⁻¹⁹C) (1.6 x 10⁻¹⁹C) / (5.35 x 10⁻¹¹m)²
= ( -2.304 x 10⁻²⁸) / (5.35 x 10⁻¹¹)²
= 8.05 x 10⁻⁸ Newton .
b). Centripetal acceleration =
v² / r .
A = (2.03 x 10⁶)² / (5.35 x 10⁻¹¹)
= 7.7 x 10²² m/s² .
That's an enormous acceleration ... about 7.85 x 10²¹ G's !
More than enough to cause the poor electron to lose its lunch.
It would be so easy to check this work of mine ...
First I calculated the force, then I calculated the centripetal acceleration.
I didn't use either answer to find the other one, and I didn't use " F = MA "
either.
I could just take the ' F ' that I found, and the 'A' that I found, and the
electron mass that I looked up, and mash the numbers together to see
whether F = M A .
I'm going to leave that step for you. Good luck !
Answers
v 2 = 2.00 · 10^8 m/s
The index of refraction:
n = v 1 / v 2 = 3.00 · 10^8 m/s : 2.00 · 10^8 m/s = 1.5
Answer:
The index of refraction of that medium is 1.5
Answer
The index of refraction of medium is 1.5 .
Explanation:
Equation for index of refraction is given by .
Where n is index of refraction in medium , v is speed of light in the medium and c is the speed of light in air .
As given
Light traveling through air at m/s reaches an unknown medium and slows down to
m/s.
Putting the values in the formula
Solving the above
n = 1.5
Therefore the index of refraction of medium is 1.5 .
Answers
Answers
Answer:
miuti celluar
Explanation:
Answer: It's multicellular (D)