The metal plate will have a net positive charge of +Q. This is due to charging by induction when a +Q charge is brought near it while grounded. Opening the switch before removing the charge leaves the induced +Q charge on the plate.
The metal plate's charge after a
+Q
charge is brought near it, the switch is opened and the charge is removed can be explained by understanding the process of
charging by induction
and the behavior of
charge on a conductor
. When the +Q charge is brought near the metal plate, it induces a -Q charge on the plate's closest surface due to the opposite charge attraction. This leaves an equal +Q charge on the farthest surface of the metal plate, as charges inside a conductor distribute to the outer surfaces in static equilibrium. When the switch connecting the plate to ground is opened, the +Q charge on the far side of the plate can't flow to ground and remains on the plate. Removing the +Q charge after that doesn't change the plate's charge as the system is no longer closed; it is now a
net positive charge
of +Q on the metal plate.
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Answer:
Approximately , assuming that the runway is level, and that air resistance is negligible at the start of take-off.
Explanation:
The acceleration of this aircraft can be found in the following steps:
Assume that when the plane just started the take-off, the air resistance (drag) on this aircraft is negligible. Forces on this aircraft during takeoff would include:
Under the assumption that the plane is on a level runway, forces in the vertical direction would be balanced. The only unbalanced force would be thrust, which is in the horizontal direction. Hence, the net force on this aircraft would be equal to thrust.
If the engine force is at the maximum value, the thrust and the net force on the aircraft would be . Divide the net force on this aircraft by mass to find acceleration:
.
In other words, the acceleration of this aircraft would be no greater than approximately under the assumptions.
The acceleration of the Boeing 737-900 during take-off, calculated using Newton's second law of motion (Force = Mass x Acceleration), is approximately 1.55 m/s².
The acceleration of the Boeing 737-900 during take-off can be calculated using Newton's second law of motion, which states that Acceleration = Force/Mass. In this case, the force is the maximum engine force, and the mass is the mass of the airplane. So, acceleration (a) = Force (F) / Mass (m) = 121,000 N / 78,200 kg = 1.548 m/s². Therefore, the closest answer to this calculation would be A) 1.55 m/s².
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The velocity of the pillow after 4 seconds is -45.2 m/sec and this can be determined by using the velocity formula.
Given :
A pillow is thrown downward with an initial speed of 6 m/s.
The equation of velocity is used in order to determine the pillow's velocity after 4 seconds.
v = u + at
where 'v' is the final velocity, 'a' is the acceleration due to gravity, 'u' is the initial velocity, and 't' is the time.
Now, substitute the known terms in the above equation in order to determine the pillow's velocity after 4 seconds.
v = -6 - 9.8 (4)
Simplify the above equation.
v = -6 - 39.2
v = -45.2 m/sec
So, the velocity of the pillow after 4 seconds is -45.2 m/sec.
For more information, refer to the link given below:
Given :
Initial velocity, u = -6 m/s.
Time taken, t = 4 seconds.
Acceleration due to gravity, .( Here negative sign means downward direction )
To Find :
Velocity after 4 seconds.
Solution :
By equation of motion.
v = u + at
Here , a = g.
v = u + gt
v = -6 + (-9.8)×4
v = -6 + (-39.2)
v = -45.2 m/s
Therefore, velocity after 4 seconds is -45.2 m/s.
Hence, this is the required solution.
In air
The speed of sound is slowest in air because sound depends on the medium it goes through and it is made from the vibrations passed on by particles in the medium to the next. In the air, the particles are the most far apart compared to the other two medium.
hope this helps! Giving me brainliest answer would be appreciated
Answer:
508Hz
Explanation:
A tuning fork with a frequency of 512 Hz is used to tune a violin. When played together, beats are heard with a frequency of 4 Hz. The string on the violin is tightened and when played again, the beats have a frequency of 2 Hz. The original frequency of the violin was ______.
When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - this phenomenon is beat production
frequency is the number of oscillation a wave makes in one seconds.
f1-f2=beats
therefore f1=512Hz
f2=?
beats=4Hz
512Hz-f2=4Hz
f2=512-4
f2=508Hz
the original frequency of the violin is 508Hz
The original frequency of the violin was 508 Hz. This is based on the principle of beats, where the beat frequency is the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
The original frequency of the violin string can be found using the principle of beats. The frequency of the beats is equal to the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
Initially, the beat frequency was heard as 4 Hz. This indicates that the original frequency of the violin was either 512 Hz + 4 Hz = 516 Hz, or 512 Hz - 4 Hz = 508 Hz. However, when the violin string was tightened, the beat frequency decreased to 2 Hz, which means the frequency of the note it was producing increased.
Therefore, the violin must have initially been producing a note with lower frequency (508 Hz), and even after tightening the string, the note it now produces (510 Hz) remains lower than that of the tuning fork.
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