A basketball player made 40% of the shots she attempted. If she made 32 baskets, how many shots did she attemp A.32 B.40 C.64 D. 80
Answers
32/40 *100
Precent proportions
32/x = 40/100
Cross multiply
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log(x–4)+log(x+3)=2logx
Answers
Answers
Square root of 135 is approximately 11.61895, so it's closest to 11 and 12.
#3:
Square root of 200 is approximately 14.1421356, so it's closest to 14 and 15.
#4:
Square root of 192 is approximately 13.8564065, so it's closest to 13 and 14.
#5:
Square root of 37 is approximately 6.08276253, so it's closest to 6 and 7.
√200 = 14,14213562373095, so two whole numbers closest to that are 14 and 15
√192 = 13,85640646055102, so two whole numbers closest to that are 13 and 14
√37 = 6,08276253029822, so two whole numbers closest to that are 6 and 7
Answers
10,503,970
10,503,097
1,503,097
10,053,097
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Just add all of the numbers together
and then add the commas. (:
-3x-2y=-12 by substitution
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Answer: x = 0.25, y = 5.625 or (,
)
Step-by-step explanation:
To solve by substitution, we will first isolate one of the variables in one of the given equations.
-7x - 2y = -13 ➜ y = -3.5x + 6.5
Then, we will substitute this into the other given equation and solve for x.
-3x - 2y = -12
-3x - 2(-3.5x + 6.5) = -12
-3x + 7x - 13 = -12
4x = 1
x = 0.25
Lastly, we will substitute this value of x into the equation we solved for to find y.
y = -3.5x + 6.5
y = -3.5(0.25) + 6.5
y = 5.625
Answers
Answer:
The possible ages of the four grandchildren are a = 4, b = 19, c = 26, and d = 34
Step-by-step explanation:
The given parameters are;
The number of grandchildren in the family = 4
The product of the ages of the four grand children = 67184
The age of the youngest grandchild < 10
The age of the oldest grandchild = 30 + The age of the youngest grandchild
Let a represent the age of the youngest grandchild, and let b, and c represent the ages of the other two intermediate grandchild
Therefore, we have;
a < 10
The age of the oldest grandchild = a + 30 < 10 + 30
∴ The age of the oldest grandchild < 40
The product of the ages of the four grandchildren = a × b × c × (a + 30) = 67184
The factors of 67184 that are between 1 and 40 are;
1, 2, 4, 8, 13, 16, 17, 19, 26, 34, 38
Taking a = 8, we have;
The age of the oldest grandchild × The age of the youngest grandchild = a × (a + 30) = 8 × 38 = 342
Therefore. a × b = 67184/(a × (a + 30) = 196.44
Therefore, a ≠ 8
For a = 4, we have the age of the oldest grandchild = a + 30 = 4 + 30 = 34
The age of the oldest grandchild × The age of the youngest grandchild = a × (a + 30) = 4 × 34 = 136
Therefore. a × b = 67184/(a × (a + 30) = 494
We find that the other factors of 67184, which are 19 and 26 have a product of 494
Therefore, the possible ages of the four grandchildren are a = 4, b = 19, c = 26, and d = 34
To give, 4 × 19 × 26 × 34 = 67,184.